Answer:
Option C
Step-by-step explanation:
You forgot to attach the expression that models the cost of the camping trip during the three days. However, by analyzing the units, the answer can be reached.
The total cost has to be in units of $.
There are two types of costs in the problem:
Those that depend on the number of days ($/day
)
Those that depend on the number of students and the number of days ($/(student * day))
If there are 3 days of camping and b students, then you have to multiply the costs that depend on the days by the number of days (3), and the costs that depend on the number of students you have to multiply them by 'b'
So, if the costs that must be multiplied by 'b' are only those that depend on the number of students, the coefficient of b must be:
3 days (Cost of training + Cost of food Miscellaneous expenses :).
Therefore the correct answer is option C:
C. It is the total cost of 3 days per student of Mr. Brown, with training, food and miscellaneous expenses.
The expression that represents the total expense should have a formula similar to this:
![y = (3 days) *([\frac{20.dollars}{(day * student)} + \frac{30.dollars}{(student * day)} + \frac{50.dollars}{(student * day)}] b + \frac{200}{day}) + 1050.dollars](https://tex.z-dn.net/?f=y%20%3D%20%283%20days%29%20%2A%28%5B%5Cfrac%7B20.dollars%7D%7B%28day%20%2A%20student%29%7D%20%2B%20%5Cfrac%7B30.dollars%7D%7B%28student%20%2A%20day%29%7D%20%2B%20%5Cfrac%7B50.dollars%7D%7B%28student%20%2A%20day%29%7D%5D%20b%20%2B%20%5Cfrac%7B200%7D%7Bday%7D%29%20%2B%201050.dollars)
y = 3 ($ 100b + $ 200) + $ 1050
Answer:
The answer is 35 and 22
Because:
U let the numbers(#) be x and y (x will be the larger number and y the smaller number
So:
x + y =57
x = 2*y - 9
Therefore,
{2*y - 9} + y = 57
Leaving the two numbers 35 and 22
I hope I could help
I believe it would be 1.5 cm squared because 7.5/5 = 5
Answer:
s is equal to 2
Step-by-step explanation:
We can tell if this is a factor of the polynomial shown by using the remainder theorem.
First, we need to set x + 1 equal to 0.
x + 1 = 0
Now, we solve for x.
x = -1
Now, we can plug this value into the polynomial, and if the solution is 0, it means there is a remainder of 0, which means they divide perfectly.
(-1)^3 - 10(-1)^2 + 27(-1) - 12 = -50
x + 1 is not a factor of the provided polynomial.