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Molodets [167]
3 years ago
9

How do you solve X/14=-21

Mathematics
1 answer:
Ket [755]3 years ago
8 0
You multiply -21 by 14 to find x, and that would be -21 x 14 = -294, and that is your answer. 
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Write the explicit formula for the geometric sequence.<br><br> 64, 32, 16, 8, ...
Setler [38]

Answer:

aₙ = 1/2 x aₙ₋₁     n≥2

Step-by-step explanation:

aₙ = 1/2 x aₙ₋₁     n≥2  

a₁ = 64

a₂ = 1/2 x 64 = 32

a₃ = 1/2 x 32 = 16

7 0
3 years ago
What is the coordinates of the center of an ellipse defined by the equation 16x^2 + 25y^2 + 160x - 200y + 400 = 0 ? Please give
pickupchik [31]

16x^2 + 25y^2 + 160x - 200y + 400 = 0     Rearrange and regroup.

(16x^2 + 160x) + (25y^2 - 200y ) = 0-400.     Group the xs together and the ys together.

16(X^2 + 10x) + 25(y^2-8y) = -400.     Factorising.

We are going to use completing the square method.

Coefficient of x in the first expression = 10.

Half of it = 1/2 * 10 = 5. (Note this value)

Square it = 5^2  = 25.     (Note this value)


Coefficient of y in the second expression = -8.

Half of it = 1/2 * -8 = -4. (Note this value)

Square it = (-4)^2  = 16. (Note this value)


We are going to carry out a manipulation of completing the square with the values

25 and 16.  By adding and substracting it.


16(X^2 + 10x) + 25(y^2-8y) = -400

16(X^2 + 10x + 25 -25) + 25(y^2-8y + 16 -16) = -400

Note that +25 - 25 = 0.    +16 -16 = 0. So the equation is not altered.

16(X^2 + 10x + 25) -16(25) + 25(y^2-8y + 16) -25(16) = -400


16(X^2 + 10x + 25) + 25(y^2-8y + 16)  = -400 +16(25) + 25(16)    Transferring the terms -16(25) and -25(16)

to other side of equation.  And 16*25 = 400


16(X^2 + 10x + 25) + 25(y^2-8y + 16)  = 25(16)


16(X^2 + 10x + 25) + 25(y^2-8y + 16)  = 400

We now complete the square by using the value when coefficient was halved.


16(x-5)^2 + 25(y-4)^2  = 400

Divide both sides of the equation by 400


(16(x-5)^2)/400 + (25(y-4)^2)/400  = 400/400              Note also that, 16*25 = 400.


((x-5)^2)/25 + ((y-4)^2)/16  = 1

((x-5)^2)/(5^2) + ((y-4)^2)/(4^2)  = 1


Comparing to the general format of an ellipse.

((x-h)^2)/(a^2) + ((y-k)^2)/(b^2)  = 1


Coordinates of the center = (h,k).

Comparing   with above   (x-5) = (x - h) , h = 5.

Comparing   with above   (y-k) = (y - k) , k = 4.

Therefore center = (h,k) = (5,4).

Sorry the answer came a little late.  Cheers.

3 0
3 years ago
How many 6 digit different locker combinations are possible if no repeat numbers are allowed?
Alex_Xolod [135]

Since we are trying to find the number of sequences can be made <em>without repetition</em>, we are going to use a combination.


The formula for combinations is:

_n C _k = \dfrac{n!}{k! (n - k)!}

  • n is the total number of elements in the set
  • k is the number of those elements you are desiring

Since there are 10 total digits, n = 10 in this scenario. Since we are choosing 6 digits of the 10 for our sequence, k = 6 in this scenario. Thus, we are trying to find _{10} C _6. This can be found as shown:

_{10} C _6 = \dfrac{10!}{6! \cdot 4!} = \dfrac{10 \cdot 9 \cdot 8 \cdot 7}{4!} = \dfrac{5040}{24} = 210


There are 210 total combinations.

7 0
3 years ago
Mr. Anderson made the following box-and-whisker graph of the quiz grades in his chemistry class.
Pachacha [2.7K]

Answer:

77

Step-by-step explanation:

I did the question and I got it correct.

3 0
3 years ago
Read the passage about Ötzi the Iceman.
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A Historian because they are describing what they see years later
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