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Sonja [21]
2 years ago
7

Is the graph a linear function, no name and function, or relation (non-functioning)?

Mathematics
1 answer:
lozanna [386]2 years ago
7 0

Answer:

no name and function

Step-by-step explanation:

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Can anyone explain how to do any of this?
pashok25 [27]

Answer:

qn 10. 15mn² - 23m²n +4m³

Step-by-step explanation:

1. distribute 4m through the parenthesis

8mn² - 12m²n + 4m³ - 2n(5m² - 3nm) + nm(n-m)

2. use the commutative property to reorder the terms

8mn² - 12m²n + 4m³ - 2n(5m² - 3mn) + mn(n - m)

3. distribute -2n through the remaining parenthesis

8mn² - 12m²n + 4m³ -10m²n + 6mn² + mn² - m²n

4. collect like terms

8mn² + 6mn² + mn² - 12m²n - 10m²n - m²n + 4m³

5. complete bodmas

15mn² - 23m²n +4m³

that's is how you do it so the answer is

15mn² -23m²n + 4m³

5 0
3 years ago
2813 Divided by 12 and remainder
maw [93]

Answer:

234.416666667

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Encuentra el área total de la superficie del prisma cuadrangular??​
Alex787 [66]

Superficie total de un prisma

La fórmula general para el área de superficie total de un prisma recto es T. S. A. = ph + 2B donde p representa el perímetro de la base, h la altura del prisma y B el área de la base.

¡Espero que esto ayude!

8 0
2 years ago
For the distribution shown below which of the following is true
soldi70 [24.7K]
BEAUTIFUL ! Nothing shown below and no choices. A perfect twofer !
7 0
2 years ago
Please help!!
Soloha48 [4]

Step-by-step explanation:

Given points are:

(-1,\:3)=(x_1,\: y_1) \:\&\:(1, \:7)=(x_2,\:y_2)

Equation of line in two point form is given as:

\frac{y-y_1 }{y_1 - y_2}  =  \frac{x-x_1 }{x_1 - x_2} \\  \\  \therefore \:  \frac{y - 3}{3 - 7}  =  \frac{x - ( - 1)}{ - 1 - 1}  \\  \\ \therefore \:  \frac{y - 3}{ - 4}  =  \frac{x  + 1}{ - 2}  \\  \\ \therefore \:  \frac{y - 3}{ 2}  =  \frac{x  + 1}{ 1}  \\  \\ \huge \purple{ \boxed{\therefore \:y - 3 = 2(x + 1)}} \\ this \: is \: the \: equation \: of \: line \: in \:  \\ point - slope \: form.\\simplifying \: it \: further \: we \: find: \\  y - 3 = 2x + 2 \\  \\ \therefore \:y = 2x + 2 + 3 \\  \\  \huge \red{ \boxed{\therefore \:y = 2x + 5}} \\ this \: is \: the \: equation \: of \: line \: in \:  \\  slope - intercept \: form.

3 0
3 years ago
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