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andrew11 [14]
3 years ago
13

Someone help please I'm really stuck on these questions and I need help please I need to bring this in tomorrow please help

Mathematics
1 answer:
AysviL [449]3 years ago
7 0
1) 1
2) PA: between 2 and 3.
2) PB: Unsure about it.
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Tickets sold in advance for a play cost $3 each. Tickets sold at the
nataly862011 [7]
80 tickets were purchased at the door.

80 5$ tickets purchased at the door equals 400$
20 3$ tickets purchased in advance equals 60$

Total of 460$
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3 years ago
You have $1000 to invest in two different accounts. In order to save the money you need for college, you need to average 6.6 per
Katena32 [7]

Answer:

B) $400 in 5%, $600 in 7%

Step-by-step explanation:

First, convert R as a percent to r as a decimal

r = R/100

r = 6.6/100

r = 0.066 rate per year,

Then solve the equation for A

A = P(1 + r/n)nt

A = 10,000.00(1 + 0.066/12)(12)(7.5)

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A = $16,382.75

Therefore, you will need to invest $400 in 5%, $600 in 7% acoounts

8 0
3 years ago
1. Nancy is purchasing a $200 coat at 15% off. What is the total amount<br> Nancy must pay?
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200 * 0.15 = $30 off
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Nancy must pay $170
3 0
3 years ago
Read 2 more answers
Heeeeeeeeeeeeelp meeeeeeeeeeeeeeeee
AlexFokin [52]
The answer is 7 because you are dividing the output to the input you will get 8 for each so therefore you divide 56 by 8 to get 7
7 0
3 years ago
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John runs a computer software store. Yesterday he counted 123 people who walked by the store, 56 of whom came into the store. Of
vaieri [72.5K]

Answer:

a) There is a 45.53% probability that a person who walks by the store will enter the store.

b) There is a 41.07% probability that a person who walks into the store will buy something.

c) There is a 18.70% probability that a person who walks by the store will come in and buy something.

d) There is a 58.93% probability that a person who comes into the store will buy nothing.

Step-by-step explanation:

This a probability problem.

The probability formula is given by:

P = \frac{D}{T}

In which P is the probability, D is the number of desired outcomes and T is the number of total outcomes.

The problem states that:

123 people walked by the store.

56 people came into the store.

23 bought something in the store.

(a) Estimate the probability that a person who walks by the store will enter the store.

123 people walked by the store and 56 entered the store, so T = 123, D = 56.

So

P = \frac{D}{T} = \frac{56}{123} = 0.4553

There is a 45.53% probability that a person who walks by the store will enter the store.

(b) Estimate the probability that a person who walks into the store will buy something.

56 people came into the store and 23 bought something, so T = 56, D = 23.

So

P = \frac{D}{T} = \frac{23}{56} = 0.4107

There is a 41.07% probability that a person who walks into the store will buy something.

(c) Estimate the probability that a person who walks by the store will come in and buy something.

123 people walked by the store and 23 came in and bought something, so T = 123, D = 23.

So

P = \frac{D}{T} = \frac{23}{123} = 0.1870

There is a 18.70% probability that a person who walks by the store will come in and buy something.

(d) Estimate the probability that a person who comes into the store will buy nothing.

Of the 56 people whom came into the store, 23 bought something. This means that 56-23 = 33 of them did not buy anything. So:

D = 33, T = 56

P = \frac{D}{T} = \frac{33}{56} = 0.5893

There is a 58.93% probability that a person who comes into the store will buy nothing.

8 0
3 years ago
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