There are two numbers whose sum is 64. The larger number subtracted from 4 times the smaller number gives 31. Then the numbers are 45 and 19
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Solution:</u></h3>
Given that, There are two numbers whose sum is 64.
Let the number be a and b in which a is bigger.
Then, a + b = 64 ------ eqn (1)
The larger number subtracted from 4 times the smaller number gives 31.
4 x b – a = 31
4b – a = 31 ----- eqn (2)
We have to find the numbers.
So, from eqn (2)
a = 4b – 31
Subatitute a in (1)
4b – 31 + b = 64
On solving we get
5b = 64 + 31
5b = 95
b = 19
So, b = 19, then eqn 1
a + 19 = 64
On simplification,
a = 64 – 19
a = 45
Hence, the two numbers are 45 and 19
Answer:
squaare root of 70<pi squared<10
Step-by-step explanation:
Talking about square root of 70, you can take the answer by approximation. u know square of eight is sixty four and square of nine is eighty one. so 70's square root shluld be between eight and nine. And as the value of pi is 3.14... when square of pi is considerd it should be >9 but <10 as pi>3. So 10 become te greatest
If you show that the example is showing a false statement then you are disproving the example/problem.
The answer to this will be a positive multiply 3 and 11 you'll get 33 and multiply 4 and 5 and you'll get 20
33/20
Answer:
0.5 < x < 16.5
Step-by-step explanation:
8.5 - 8.0 < x < 8.5 + 8.0 =
0.5 < x < 16.5
<em>Hope that helps! :)</em>
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<em>-Aphrodite</em>
