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3 years ago

Help for brainly and poibts

Mathematics

2 answers:

Anon25 [30]3 years ago

5 0

It would be more than 1 because the 3/5 + 3/4 is equal to 1 7/20

lana [24]3 years ago

3 0

It would be more than one because 3/5 + 3/4 equals 1 7/20

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Please help!!!!!!!!!!!

Temka [501]

9514 1404 393

Answer:

(d) h = 2A/b

Step-by-step explanation:

Multiply both sides of the equation by the inverse of the coefficient of h.

$A = \dfrac{1}{2}bh=\dfrac{b}{2}\cdot h\\\\\dfrac{2}{b}\cdot A=h\\\\\boxed{h=\dfrac{2A}{b}}$

4 0

3 years ago

In the diagram of circle C, what is the measure of 21?

kondaur [170]

Answer:

If I know what diagram you're referring to, which I believe I do, the answer is: ∠1=(1/2)[106°-36°]=35°

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3 years ago

A statistics textbook chapter contains 60 exercises, 6 of which are essay questions. A student is assigned 10 problems. (a) What

Scilla [17]

Answer:

a) P=0.3174

b) P=0.4232

c) P=0.2594

d) The shape of the hypergeometric, in this case, is like a binomial with mean np=1.

Step-by-step explanation:

The appropiate distribution to model this is the hypergeometric distribution:

$P(X=x)=\frac{\binom{s}{x}\binom{N-s}{M-x}}{\binom{N}{M}}=\frac{\binom{6}{x}\binom{54}{10-x}}{\binom{60}{10}}$

a) What is the probability that none of the questions are essay?

$P(X=0)=\frac{\binom{6}{0}\binom{54}{10-0}}{\binom{60}{10}}\\\\P(X=0)=\frac{1*(54!/(10!*44!)}{60!/(10!*50!)} =\frac{2.3931*10^{10}}{7.5394*10^{10}} = 0.3174$

b) What is the probability that at least one is essay?

$P(X=1)=\frac{\binom{6}{1}\binom{54}{9}}{\binom{60}{10}}\\\\P(X=1)=\frac{6*(54!/(9!*43!)}{60!/(10!*50!)} =\frac{3.1908*10^{10}}{7.5394*10^{10}} =0.4232$

c) What is the probability that two or more are essay?

$P(X\geq2)=1-(P(0)+P(1))=1-(0.3174+0.4232)=1-0.7406=0.2594$

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3 years ago

Of the following sets, which represents a function? Situation A = {student's name, all the colors that the student likes} Situat

luda_lava [24]

Answer:

Situation A

Step-by-step explanation:

please mark as brainlist answer

8 0

3 years ago

Read 2 more answers

Factor completely:<br>64 - y^3

madam [21]

From your equation, you can see that you have a difference of two cubes (aka two cubes being subtracted): 64, which is $4^{3}$ , and $y^{3}$ .

There is rule for the difference of two cubes:
The difference of two cubes is equal to the difference of the cube roots times a binomial, which is the sum of the squares of the roots plus the product of the roots.

That sounds pretty confusing, but it's much easier to understand when put mathematically. Let's say our two cubes are $a^{3}$ and $b^{3}$ . The difference of those two cubes is:
$a^{3} - b^{3} = (a - b)( a^{2} + ab + b^{2})$

In our problem, a = 4 (since $a^{3}$ = 64) and b = y (since $b^{3} = y^{3}$ . Plug these values into the rule to find the factor of $64 - y^3$ :
$64 - y^3 \\
= (4 - y)( 4^{2} + 4y + y^{2}) \\
= (4 - y)( 16 + 4y + y^{2})$

-----

Answer: $(4 - y)( 16 + 4y + y^{2})$

8 0

3 years ago