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3 years ago

Find the value of this expression if x = -9. x2 + 3 x +6

Mathematics

1 answer:

iren [92.7K]3 years ago

7 0

Answer:

Step-by-step explanation:

x² + 3 = (-9)² + 3 { (-9)² = -9 *-9 = 81}

= 81 + 3

= 84

x + 6 = -9 + 6 = -3

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HELP MATH ._. rbiufb3fuib3fu4

Genrish500 [490]

Answer:

Step-by-step explanation:

9/2 is the slope. Slope defines how steep is the straight line.

Slope = change in y ÷ change in x

In this model, 9 refers to the vertical distance between two points

and 2 refers to the horizontal distance between two points.

9/2 is a positive slope. It indicates that if 'x' increases, y also increase.

4 0

2 years ago

Find sinϴ and cosϴ if tanϴ=1/4 and sinϴ>0

eduard

If you're using the app, try seeing this answer through your browser: brainly.com/question/2787701

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$\mathsf{tan\,\theta=\dfrac{1}{4}\qquad\qquad(sin\,\theta\ \textgreater \ 0)}\\\\\\
\mathsf{\dfrac{sin\,\theta}{cos\,\theta}=\dfrac{1}{4}}\\\\\\
\mathsf{4\,sin\,\theta=cos\,\theta\qquad\quad(i)}$

Square both sides:

$\mathsf{(4\,sin\,\theta)^2=(cos\,\theta)^2}\\\\
\mathsf{4^2\,sin^2\,\theta=cos^2\,\theta}\\\\
\mathsf{16\,sin^2\,\theta=cos^2\,\theta\qquad\qquad(but,~cos^2\,\theta=1-sin^2\,\theta)}\\\\
\mathsf{16\,sin^2\,\theta=1-sin^2\,\theta}$

$\mathsf{16\,sin^2\,\theta+sin^2\,\theta=1}\\\\
\mathsf{17\,sin^2\,\theta=1}\\\\
\mathsf{sin^2\,\theta=\dfrac{1}{17}}\\\\\\
\mathsf{sin\,\theta=\pm\,\sqrt{\dfrac{1}{17}}}\\\\\\
\mathsf{sin\,\theta=\pm\,\dfrac{1}{\sqrt{17}}}$

Since $\mathsf{sin\,\theta}$ is positive, you can discard the negative sign. So,

$\mathsf{sin\,\theta=\dfrac{1}{\sqrt{17}}\qquad\quad\checkmark}$

Substitute this value back into $\mathsf{(i)}$ to find $\mathsf{cos\,\theta:}$

$\mathsf{4\cdot \dfrac{1}{\sqrt{17}}=cos\,\theta}\\\\\\
\mathsf{cos\,\theta=\dfrac{4}{\sqrt{17}}\qquad\quad\checkmark}$

I hope this helps. =)

Tags: <em>trigonometric identity relation trig sine cosine tangent sin cos tan trigonometry precalculus</em>

7 0

3 years ago

Let f(x)=x+3 and g(x)=1/x. The graph of (f*g)(x) is shown below.

Vlad [161]

For this case we have the following functions:
$f (x) = x + 3

g (x) = 1 / x$ When composing the functions we have:
$(fog) (x) = f (g (x))
$
Substituting values we have:
$(fog) (x) = ((1 / x) +3)
$
Rewriting:
$(fog) (x) = 1 / x + 3
$
The function has a horizontal asymptote at y = 3.
Therefore, the range of the function is all reals minus y = 3.
Answer:
option 3

3 0

3 years ago

Z = { x:x is an integer, x ≥ - 3 and x ≤ + 3}

tankabanditka [31]

Answer:

If this is asking for the set:

Z = {-3, -2, -1, 0, 1, 2, 3}

Step-by-step explanation:

Z is the set of all integers and it appears that you are being asked for the values in the set Z that are within the range: -3 ≤x ≤ 3

5 0

3 years ago

Given that abcd is a rhombus, what is the value of x?

jeyben [28]

Answer:

A - 19.5

Step-by-step explanation:

A Rhombus is characterized by the diagonals meeting at a right angle. Therefore, the angle in the center is 90 degrees.

If you look at the bottom triangle, you know that the angles of a triangle add up to 180 degrees. You can say that all of the angles of the triangle added to 180 are:

(3x + 12) + (x) +(90) = 180 degrees

4x + 102 = 180 degrees combining like terms

4x + 102 - 102 = 180 - 102

4x = 78

4x/4 = 78/4

x = 19.5 degrees

4 0

3 years ago

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