In exercises 1 and 2, find m<1 and m<2. Tell which theorem you used in each case.

Which statement can be proved if you are given that SK≌LR?

MaRussiya [10]

I believe it would be D) ST ≈ TR

6 0

3 years ago

75=0.25 X 1.33N How do you solve for N

kakasveta [241]

Answer:

N=625/3

Step-by-step explanation:

1) 0.25 ⋅ 1.44N=75

2) 0.36N=75

3) 0.36N/0.36 = 75/0.36

4) N= 625/3

Hope that helps

Have a good day

5 0

2 years ago

Read 2 more answers

The appropriate translation of the phrase 11 more than 20 percent of a number is:

Arturiano [62]

Answer: True

Step-by-step explanation: 20% can also be written as 0.2 and if you know the number then you would multiply it by 0.2, then if you needed to add 11 that is exactly how you would write that equation

8 0

3 years ago

Find the IQR (interquartile range). 19, 21, 18, 17, 18, 22,46

yanalaym [24]

Answer:

4.

Step-by-step explanation:

Step 1: Formula.

$IQR=Q3-Q1$

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Step 2: Explain/define.

The interquartile range is the difference between quartile 3 and quartile 1.
Quartile 1 is the median of the upper half of a data set.
Quartile 3 is the median of the lower half of a data set.
The median is the 'middle value.'

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Step 3: Order/arrange.

In order to find the median, you must first put the numbers in numerical order.

19, 21, 18, 17, 18, 22, 46

↓

17, 18, 18, 19, 21, 22, 46

The lower half of the data set, not including the median of the whole data set, is 17, 18, and 18.

The upper half of the data set is 21, 22, and 46.

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Step 4: Solve.

17, 18, 18

21, 22, 36

Next, we find the medians of both sets.

The median of the lower half is 18 (Q1).

The median of the upper half is 22 (Q3).

Lastly, we subtract Q3 from Q1.

$22-18=4.$

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Step 5: Conclude.

I, therefore, believe the interquartile range of this data set is 4.

3 0

2 years ago

Please help me solve this short problem I’m really struggling

bearhunter [10]

Answer:

Step-by-step explanation:

In the standard form of a quadratic,

$h(x)=-x^2+v_0x+h_0$ ,

that last term, the h0, is the initial height off the ground that the object is. That means that for the first question, the irrigation system is initially 9.5 feet off the ground.

In order to answer the next question, we need to find the vertex of the parabola, because this is where the max height will occur and at how many feet away from the system. The max height is the k of the vertex and the horizontal distance away is the h of the vertex: (h, k). Thankfully, we have simple formulas to find those:

$h=-\frac{b}{2a}$ and $k=c-\frac{b^2}{4a}$ where a, b, and c come from the coefficients in the equation. For us, a = -1, b = 10, and c = 9.5. Finding h first:

$h=-\frac{10}{2(-1)}=\frac{-10}{-2}=5$

and now k:

$k=9.5-(\frac{10^2}{4(-1)})=9.5-(\frac{100}{-4} )=9.5-(-25)=9.5+25=34.5$

Summing it up, the vertex is at (5, 34.5), The interpretation of that is that "The spray reaches a max height of 34.5 feet at a horizontal distance of 5 feet away from the sprinkler head."

Next we are asked how far away from the sprinkler head the water hits the ground. To do this we factor the expression to find the zeros. The zeros tell us where the water will hit the ground after it reaches its max height and then falls back down to earth.

I used my calculator to factor this for me to get that the water will hit the ground 10.87 feet away from the sprinkler head.

7 0

3 years ago