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2 years ago

In exercises 1 and 2, find m<1 and m<2. Tell which theorem you used in each case.

Mathematics

1 answer:

solniwko [45]2 years ago

8 0

Answer:

m∠2 = 78°

Step-by-step explanation:

From the given picture,

lines 'm' and 'n' are the parallel lines and line 't' is the transverse line.

∠1 and angle with the measure of 78° are corresponding angles.

Therefore, m∠1 = 78°

m∠1 = m∠2 [Vertical angles are equal]

m∠2 = 78°

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\cfrac{(x-{{ h}})^2}{{{ a}}^2}+\cfrac{(y-{{ k}})^2}{{{ b}}^2}=1\\\\ \cfrac{(x-{{ h}})^2}{{{ b}}^2}+\cfrac{(y-{{ k}})^2}{{{ a}}^2}=1
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