In exercises 1 and 2, find m<1 and m<2. Tell which theorem you used in each case.
1 answer:
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Answer:
<u>Option C</u>
Step-by-step explanation:
Given 0.5≤ x ≤ 0.7
According to the range of x, we will check which option is true
Let x = 0.6
A.
If x = 0.6
∴0.6/3 > √0.6 ⇒ 0.2 > 0.77 ⇒ <u>Wrong inequality </u>
B. x³ > 1/x
If x = 0.6
∴ 0.6³ > 1/0.6 ⇒ 0.216 > 1.667 ⇒ <u>Wrong inequality </u>
<u></u>
C. √x > x³
If x = 0.6
∴ √0.6 > 0.6³ ⇒ 0.77 > 0.216 ⇒ <u>True inequality </u>
D. (x/3) > (1/x)
If x = 0.6
∴ 0.6/3 > 1/0.6 ⇒ 0.2 > 1.667 ⇒<u> Wrong inequality </u>
<u>So, The true inequality is option C</u>
The cotangent function is defined as the ratio between cosine and sine of a given angle, i.e.
Since you can't have zero at the denominator, the cotangent function is not defined when the sine is zero.
Let's look at your option:
, so the cotangent is defined here
, so the cotangent is not defined here
, so the cotangent is defined here
, so the cotangent is defined here