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Trava [24]
3 years ago
14

Test 645 for divisibility by 2, 3, 5, 9, and 10.

Mathematics
1 answer:
zaharov [31]3 years ago
4 0

Answer:To test for divisibility, you look for answers that are whole numbers when you divide 59859 by either 2, 3, 5, 9, or 10.

To start divide it by each of them:

59859/2=29929.5

59859/3= 19953

59859/5= 11971.8

59859/9= 6651

59859/10= 5985.9

Now look at which of the choices are whole numbers

3 and 9 are the only non decimal numbers, therefore, C would be your answer.

Step-by-step explanation:

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Select the two answer choices that apply.
Lemur [1.5K]

Answer:

its a

Step-by-step explanation:

6 0
3 years ago
how many ways can you order your favorite dessert from a menu of 8? A.) 6 B.) 40,320 C.) 6720 D.) 336​
Radda [10]

Can you tell me what do you mean exactly by menu of 8, so i can help you.

8 0
3 years ago
-6c&lt; -12<br> what will the answear be
murzikaleks [220]

Answer:c>2

Step-by-step explanation:

-6c (divide) (-6) > -12 (divide) (-6)

c>-12 (divide) (-6)

c>12 (divide) 6

c> 2

8 0
3 years ago
I need help ‼️ #10, #11 &amp; #13.
Cerrena [4.2K]

Answer: 10 : t = 16   11 : x = -8   13 : x = 0

Step-by-step explanation: Im sure about 10 and 11 but not too sure about 13 and explanations are too hard for me to explain

7 0
3 years ago
Assume that when Human Resource managers are randomly selected, 62% say job applicants should follow up within two weeks. If 25
Alenkinab [10]

Using the binomial distribution, it is found that there is a 38% probability that exactly 18 of them say job applicants should follow up within two weeks.

<h3>How to find that a given condition can be modelled by binomial distribution?</h3>

Binomial distributions consists of n independent Bernoulli trials.

Bernoulli trials are those trials that end up randomly either on success (with probability p) or on failures( with probability 1- p = q (say))

The probability that out of n trials, there'd be x successes is given by

P(X =x) = \: ^nC_xp^x(1-p)^{n-x}

Binomial probability distribution  

P(X =x) = \: ^nC_xp^x(1-p)^{n-x}

The parameters are:

n is the number of trials.

x is the number of successes.

p is the probability of success on a single trial.

In this problem:

62% say job applicants should follow up within two weeks, p = 0.62

25 managers are selected, n = 25

The probability that exactly 18 of them say job applicants should follow up within two weeks is P ( X = 18)

P( X > 18) = 1 -  ( X = 18)

= 1 - 0.62

= 0.38

38 % probability that exactly 18 of them say job applicants should follow up within two weeks.

Learn more about binomial distribution here:

brainly.com/question/13609688

#SPJ1

8 0
2 years ago
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