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3 years ago

How much of 10% HCl and 35% HCl would be needed to mix and produce 60 liters of 25% HCl?

Mathematics

2 answers:

andreyandreev [35.5K]3 years ago

8 0

Answer:

about 36 and 24 liters

Step-by-step explanation:

a+b = 60 1

let A multiplied by 10 percent and B multiplied by 35 percent then

10 a + 35 b = 1500 ( 60 * 25 ) 2

add no. 1 to 2 and multiply no.1 by -10

-10 a+ -10 b = -600

10 a+ 35 b = 1500 adding

then 25 b = 900 then b = 36 liter

then a = 24 liter

puteri [66]3 years ago

5 0

Answer:

Equation:

HCL + HCL = HCL 

0.30x + 0.45(50-x) = 0.35*50

Multiply thru by 100 to get:

30x + 45*50 - 45x = 35*50

-15x = -10*50

x = (2/3)50

x = 33 1/3 liters (amt. of 30% solution needed in the mixture)

50-x = 16 2/3 liters (amt. of 45% solution needed in the mixture)

=============

Step-by-step explanation:

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3 years ago

Read 2 more answers

The lifetime of a machine part has a continuous distribution on the interval (0, 50) with probability density function f, whe

Strike441 [17]

Answer:

Probability that the lifetime of the machine part is less than 13 = 0.6782

Step-by-step explanation:

given that $f(x)=(10+x)^{-2}$

Normalizing the function we get

$\int_{0 }^{50}cf(x)dx=1$

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3 years ago