A = 6
B = 9
C = 15
D = ?
From A to B, 6 + 3 = 9
From B to C, 9 + 6 = 15
From C to D, 9 + x = ?
The first time, you added 3, for the second time, you added three to the three you are adding, making it 6. So for x, x = 6 + 3, which = 9
9 + 9 = 18
D = 18 should be your answer
hope this helps
Answer:
16 responses
Step-by-step explanation:
we know that
A geometric sequence, is a sequence of numbers where each term after the first is found by multiplying the previous one by a fixed, non-zero number called the common ratio.
where
a_n----> 
term of the sequence
r ---> is the common ratio
a ---> the first term of the sequence
substitute
For n=12
substitute
Usually, we use the number line to solve inequalities with the symbols,
<
,
≤
,
>
, and
≥
.(the second and last one was rather hard to find on my keyboard) In order to solve an inequality using the number line, though, just turn
the inequality sign to an equal sign. Then, solve the equation. Next step,
graph the point on the number line (remember to graph as an open circle if the
original inequality was <, or >). The number line should now be
divided into 2 regions, one to the left of the graphed point, and one to the
right of said point.
After that, pick a point in both regions and "test" it, check to see if it satisfies
the inequality when plugged in for the variable. If it does, draw a darker line from the point into that region, with an
arrow at the end. That is the solution to the equation: if one
point in the region satisfies the inequality, the entire region will
satisfy the inequality.
I had to check back in an old textbook to remember all of that. Sorry about the earlier answer. That was rather foolish to do so without actually understanding the question.
Answer:
B
Step-by-step explanation:
