Answer:
![\sqrt[5]{2^4}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B2%5E4%7D)
Step-by-step explanation:
Maybe you want 2^(4/5) in radical form.
The denominator of the fractional power is the index of the root. Either the inside or the outside can be raised to the power of the numerator.
![2^{\frac{4}{5}}=\boxed{\sqrt[5]{2^4}=(\sqrt[5]{2})^4}](https://tex.z-dn.net/?f=2%5E%7B%5Cfrac%7B4%7D%7B5%7D%7D%3D%5Cboxed%7B%5Csqrt%5B5%5D%7B2%5E4%7D%3D%28%5Csqrt%5B5%5D%7B2%7D%29%5E4%7D)
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In many cases, it is preferred to keep the power inside the radical symbol.
I only see the store question but the answer is correct, 600
The energy of the reaction is 9 kJ/mol and the reaction is endothermic.
<h3>What is the total energy of the reaction?</h3>
We know that in a reaction, there could be loss or gain of energy. If there is a loss of energy in a reaction, it means that the reaction is exothermic and heat is given out. If heat is gained in the reaction, it means that the reaction is endothermic and heat is absorbed.
Given that;
Energy of the products = 590 kJ/mol
Energy of the reactants = 581 kJ/mol
Using;
Energy of products - Energy of reactants
= 590 kJ/mol - 581 kJ/mol
= 9 kJ/mol
Learn more about energy of reaction:brainly.com/question/2223923
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1. <span> rectangle
2. </span><span>x2 + y2 = 5
3. 64
4. I don't know
5. possibly -</span>
