For a right triangle with legs legnth a and b and hyptonuse c
a^2+b^2=c^2
9 feet from base, that's one leg
wire is hypotnuse, it's 1 more than height on tree
c=b+1
so
9^2+b^2=(b+1)^2
81+b^2=b^2+2b+1
minus b^2+1 from both sides
80=2b
divide both sides by 2
40=b
c=b+1
c=40+1
c=41
legnth of wire is 41ft
Answer:
8
Step-by-step explanation:
hope i helped have a verey good day
Can I see like a picture or what do do I need to do like more info
Answer:
-65 i suppose
Step-by-step explanation:
Answer:
y = 3x + 1
Step-by-step explanation:
y= -1/3x
perpendicular so y = 3x + b
the line goes through (1,4), so substitute to find the value b , which is where the line intersects with the y axis.
4 = 3*1 +b
so b = 1
y = 3x + 1
