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Romashka-Z-Leto [24]
4 years ago
14

there are 6 muffins in a package how many packages will be needed to be 48 people in each person has two muffins

Mathematics
1 answer:
deff fn [24]4 years ago
7 0
You need 92 muffins in total then you dived by 6 = 16
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Please help me!<br><br> Solve for x<br><br> 4−(2x+4)=5
Helga [31]
<span>4−(2x+4)=5
4 - 2x - 4 = 5
  -2x = 5
     x = -5/2
     x = - 2.5</span>
5 0
4 years ago
Read 2 more answers
G(x) = x² + 3h(x)=-4xFind (g/h)(x)
34kurt
\begin{gathered} g(x)=x^2+3 \\ h(x)=-4x \end{gathered}

We need to find

\frac{g}{h}(x)=\frac{x^2+3}{-4x};x\ne0

5 0
1 year ago
Could someone help me? I have to do a report in Earth and Space Science, a 'mineral report' whats a mineral I should write about
lana66690 [7]

you could write about quartz it's a pretty interesting mineral

here are some facts

it's very well known - occurs in all forms and colors - has the most variety names of any other mineral - amethyst, citrine, and agate are commonly recognized as individual minerals but they're just varieties of quartz - quartz can be heated to intensify color - often forms inner lining of geodes - rock type can be igneous, sedimentary, or metamorphic - occurs in almost every mineral environment

3 0
3 years ago
According to the Center for Disease Control and Prevention (CDC), up to 20% of Americans contract the influenza virus each year,
12345 [234]

Answer:

(1) a. 0.0009

(2) d. 0.640

(3)

  • a. P(A and B) = 0.06.
  • b. P(A or B) = 0.70.

(4)Not disjoint

(5) a. nearly 0.

(6)b. 0.919

Step-by-Step Explanation:

(1)Probability of a baby being born with a birth defect =3%=0.03

The probability that both babies have birth defects=0.03 X 0.03= 0.0009.

(2)The probability of contracting the influenza virus each year = 20%=0.2

Therefore, the probability of not contracting the influenza virus =1-0.2=0.8

The probability that neither baby catches the flu in a given year:

=0.8 X  0.8

=0.64

(3)

P(A)=0.1

P(B)=0.6

P(A or B)=P(A)+P(B)=0.1 + 0.6 =0.7

P(A and B)=P(A)XP(B)=0.1 X 0.6 =0.06

(4)

P(A)=0.2

P(B)=0.9

Event A and B cannot be disjoint.

(5)

The probability of an American woman aged 20 to 24 having Chlamydia infection  =\dfrac{2791.5}{100000}

The probability that three randomly selected women in this age group have the infection

=\dfrac{2791.5}{100000} \times \dfrac{2791.5}{100000} \times \dfrac{2791.5}{100000} \\\\=0.00002175\\\approx 0

(6)The probability of an American woman aged 20 to 24 not having Chlamydia infection  =1-\dfrac{2791.5}{100000}

The probability that three randomly selected women in this age group do not have the infection

=\left(1-\dfrac{2791.5}{100000}\right)^3\\\\=0.9186\\\approx 0.919

7 0
4 years ago
What is this!!!!!!!!!!!!
Karo-lina-s [1.5K]

Answer:

MARK ME BRAINLIEST!! THANKS BOO!!!!!!!!!!!

Step-by-step explanation:

7 0
3 years ago
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