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tekilochka [14]
3 years ago
14

Triangle ABC has three sides with these lengths: AB = 9, BC = 40, and CA = 41. What is the value of cos C? A. 9/41 B. 40/9 C. 40

/41 D. 9/40
Mathematics
2 answers:
seraphim [82]3 years ago
5 0
The answer is letter C which is 40/41. If you draw a triangle the sides found in the cos C is BC which is equal to 40 and the CA which is equal to 41 or the 40/41. It can not be the AB since it is in the opposite side of the cos C. 
galina1969 [7]3 years ago
4 0
It's a <span>rectangular triangle because:

9² + 40² = 41²
81 + 1600 = 1681
1681 = 1681

Answer: C. cos∡C = 40/41
</span>
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Now let's say he earned $27 on Tuesday, and still earned $10 less the next day, meaning that he earns 27-10 = 17

Whatever he earns on Tuesday, subtract off 10. That's the rule to follow for this problem.

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If n reprsesent the placeholder for "amount earned on Tuesday", then we can rewrite that equation as

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In short, whatever 'n' is, subtract 10 off it. In the examples above, I used n = 15 and n = 27.

note: the order of subtraction matters. The expression n-10 is not the same as 10 - n. If you subtract in the wrong order you may get a negative value (eg: 10 - 17 = -7), but he can't earn a negative amount of dollars.

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