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3 years ago

Solve: 6(5x-3)+2=14.

Mathematics

2 answers:

umka2103 [35]3 years ago

7 0

The answer is X=1
...............

DIA [1.3K]3 years ago

6 0

X=1

Should I show you the steps?

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Please solve with explanation (high points)

Dmitrij [34]

Answer:

see the attachment photo!

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2 years ago

Use elimination to solve: NN+ND=50 5NN+10ND=450

Tomtit [17]

$5NN+10ND=450\\5(NN+2ND)=450 \\ NN+2ND=90 \\ \\ \boxed{NN=90-2ND} \\ \\ NN+ND=50 =>\boxed{NN=50-ND} \\ \\ \\ 90-2ND=50-ND \\ -2ND+ND=50-90 \\ -ND=-40 \\ \\ \boxed{ND=40} \\ \\ NN=50-ND \\ NN=50-40 \\ \\ \boxed{NN=10}$

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3 years ago

Equal functions are two functions that have _____ domains, and, for each value in the domain set, _____ range values respectivel

dimulka [17.4K]

Solution-

Answer is same, same.

Two functions are said to be equal or identical if-

(1) They have same domain.

(2) They have same Range and

(3) For same value of x (independent variable), we get same value of y (dependent variable).

7 0

3 years ago

Read 2 more answers

What is the solution of the equation (x – 5)^2 + 3(x – 5) + 9 = 0? Use u substitution and the quadratic formula to solve.

xz_007 [3.2K]

Answer:

$x = \dfrac{7 \pm 3i\sqrt{3}}{2}$

Step-by-step explanation:

(x – 5)^2 + 3(x – 5) + 9 = 0

This is a quadratic equation in x - 5.

Let u = x - 5, then the quadratic equation becomes:

u^2 + 3u + 9 = 0

We can use the quadratic formula to solve for u.

$u = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

$u = \dfrac{-3 \pm \sqrt{3^2 - 4(1)(9)}}{2(1)}$

$u = \dfrac{-3 \pm \sqrt{9 - 36}}{2}$

$u = \dfrac{-3 \pm \sqrt{-27}}{2}$

$u = \dfrac{-3 \pm 3i\sqrt{3}}{2}$

Since u = x - 5, now we substitute x - 5 for u and solve for x.

$x - 5 = \dfrac{-3 \pm 3i\sqrt{3}}{2}$

$x = \dfrac{-3 \pm 3i\sqrt{3}}{2} + 5$

$x = \dfrac{-3 \pm 3i\sqrt{3}}{2} + \dfrac{10}{2}$

$x = \dfrac{7 \pm 3i\sqrt{3}}{2}$

7 0

3 years ago

5. What are the zeros of the graph below? A -2 and 0 B-1 and 0 C 0 and 2

Fed [463]

Answer:

A. -2 and 0

Step-by-step explanation:

The curve hits both mark -2 and 0

4 0

3 years ago