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3 years ago

a store sells a toy for $24.60, regular price. today the toy is 80% of the original price, what is the sale price of the toy?

Mathematics

2 answers:

pantera1 [17]3 years ago

7 0

The answer is $19.68

solniwko [45]3 years ago

3 0

80% = 0.8

0.8 * 24.60 = 19.68

answer: <span>sale price of the toy today is $ 19.68</span>

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Use one or more properties to rewrite each expression as an expression that does not use parentheses.

maria [59]

Answer:

b + 9

Step-by-step explanation:

Given:

(b + 3) + 6

Required:

Rewrite expression without the parentheses.

SOLUTION:

(b + 3) + 6

Eliminate the parentheses

b + 3 + 6

Add like terms

b + 9

Thus:

(b + 3) + 6 = b + 9

4 0

3 years ago

One hundred items are simultaneously put on a life test. Suppose the lifetimes

romanna [79]

Answer:

a) $\mathrm{E}[\mathrm{T}]=\sum_{\mathrm{H}}^{5} \frac{200}{101-i}$

b) $\mathrm{Var}[\mathrm{T}]=\sum_{k=1}^{5} \frac{(200)^{2}}{(101-i)^{2}}$

Step-by-step explanation:

Given:

The lifetimes of the individual items are independent exponential random variables.

Mean = 200 hours.

Assume, Ti be the time between ( $i-1$ )st and the $ith$ failures. Then, the $T_{i}$ are independent with $\mathrm{T}_{\mathrm{i}}$ being exponential with rate $\frac{(101-i)}{200} .$

Therefore,

a) $E[T]=\sum_{i=1}^{5} E\left[\tau_{i}\right]$

$=\sum_{i=1}^{5} \frac{200}{101-i}$

$\therefore \mathrm{E}[\mathrm{T}]=\sum_{\mathrm{H}}^{5} \frac{200}{101-i}$

$b)$

The variance is given by, $\mathrm{Var}[\mathrm{T}]=\sum_{i=1}^{5} \mathrm{Var}[T]$

$\therefore \mathrm{Var}[\mathrm{T}]=\sum_{k=1}^{5} \frac{(200)^{2}}{(101-i)^{2}}$

7 0

3 years ago

Please please help me

Semenov [28]

X=3 because you subtract the three on both sides to get x alone. So you get: 7x=21 then you divide seven by 21 and get x=3

5 0

2 years ago

At the gift shop, they sell small greeting cards and large greeting cards. The cost of a small greeting card is $1.60 and the co

erik [133]

<h2>Explanations:</h2>

From the given question, we have the following parameters

Cost of a small greeting card = $1.60

The cost of a large greeting card = $4.05.

Cost of 5 small greeting cards = 5(1.60)

Cost of 5 small greeting cards = $8.00

Cost of 4 large greeting cards = 4(4.05)

Cost of 4 large greeting cards = $16.2

Cost of 5 small and 4 large = $8.00 + $16.2

Cost of 5 small and 4 large $24.2

Hence it would cost $24.2 to get 5 small greeting cards and 4 large greeting cards

Similarly;

Cost of x small greeting cards = 1.60x

Cost of y large greeting cards = 4.05y

Cost of small greeting cards and y large greeting cards = 1.60x + 4.05y

Hence it would cost $(1.60x + 4.05y) to get x small greeting cards and y large greeting cards

5 0

1 year ago

Hi help me please, I can't seem to figure this one out

Nastasia [14]

Answer:

x= 2.73cm

For the same angle we just work out 1cm first.

a^2+ b^2= c^2

0.82^2 + b^2 = 1^2 = changing to units 10

6.724 + b^2 = 10

10-6.724 = 2.276

Then x 3 and change units down by 10= 0.6828

Step-by-step explanation:

Below shows why we must convert to mm from cm

a^2+ b^2= c^2

0.82^2 + b^2 = 1^2 =

0.6724 + b^2 = 1

1 - 0.6724 = b = 0.2276

0.2276 x 3 = 0.6828 cm

7 0

3 years ago