To prove that <span>AEC≅ AED, we need to write following proofs or statement reasons.
It is given that points C and D are equidistant to point A. Hence,
</span><span>AD ≅ AC
Next, </span><span>CAE ≅ DAE. AE is the common side or the included side.
</span><span>
Then, </span><span>AE ≅ EA by Reflexive Property of Congruence as it is congruent to itself.
Lastly, </span><span>EAD ≅ EAC by Symmetric Property of Congruence as these triangles are mirror image of each other.
</span>
Therefore, we can conclude that AEC≅ AED by SSS or Side-Side-Side. That is when all sides of triangles are congruent then both triangles are deemed to be equal.
X=2 ? you didn’t get any paper with a diagram or something on it?
Answer: 0
Explanation: Displacement is how far something or someone is from the starting point, in this case, the frog, so it moves 18F then 6B then 12B, so 0+18-6-12=0.
Hope this helps! :)
