4000 is the answer to your question
First we need to find k ( rate of growth)
The formula is
A=p e^kt
A future bacteria 4800
P current bacteria 4000
E constant
K rate of growth?
T time 5 hours
Plug in the formula
4800=4000 e^5k
Solve for k
4800/4000=e^5k
Take the log for both sides
Log (4800/4000)=5k×log (e)
5k=log (4800/4000)÷log (e)
K=(log(4,800÷4,000)÷log(e))÷5
k=0.03646
Now use the formula again to find how bacteria will be present after 15 Hours
A=p e^kt
A ?
P 4000
K 0.03646
E constant
T 15 hours
Plug in the formula
A=4,000×e^(0.03646×15)
A=6,911.55 round your answer to get 6912 bacteria will be present after 15 Hours
Hope it helps!
X intercept is (1,0)
y intercept is (0,-4)
The area of a square is A=s2nd power,
If you could paste the answers I can do it for you.<span />
Answer:
188
Step-by-step explanation:
SR and ST are equal in length so the arc SR and arc ST also have same measurement
since the perimeter of the circle is equal to 360 and arc RT is given as 64
x = (360 - 64) / 2
x = 188
