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IrinaVladis [17]
3 years ago
14

A 128-ounce jug of milk costs $3.20, and a 64-ounce jug of milk costs $2.24. What is the difference in cost per ounce between th

e larger and the smaller jugs of milk?
brainiest
Mathematics
1 answer:
klasskru [66]3 years ago
5 0

Answer:

The 64 ounce jug of milk costs $0.010 more per ounce than the 128 ounce jug of milk/

Step-by-step explanation:

3.20/128=$0.025 per ounce jug of milk

2.24/64=$0.035 per ounce jug of milk

0.035 - 0.025 = .010

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(6)(5) =

Step-by-step explanation:

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Which expression is equivalent to
lutik1710 [3]

Answer:

\frac{\sqrt[4]{3x^2} }{2y}

Step-by-step explanation:

We can simplify the expression under the root first.

Remember to use  \frac{a^x}{a^y}=a^{x-y}

Thus, we have:

\sqrt[4]{\frac{24x^{6}y}{128x^{4}y^{5}}} \\=\sqrt[4]{\frac{3x^{2}}{16y^{4}}}

We know 4th root can be written as "to the power 1/4th". Then we can use the property  (ab)^{x}=a^x b^x

<em>So we have:</em>

<em>\sqrt[4]{\frac{3x^{2}}{16y^{4}}} \\=(\frac{3x^{2}}{16y^{4}})^{\frac{1}{4}}\\=\frac{3^{\frac{1}{4}}x^{\frac{1}{2}}}{2y}\\=\frac{\sqrt[4]{3x^2} }{2y}</em>

<em />

<em>Option D is right.</em>

8 0
4 years ago
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serious [3.7K]

Answer:

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Step-by-step explanation:

4 0
3 years ago
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Answer:

Range: {-1, 0, 1}

General Formulas and Concepts:

<u>Math</u>

  • Number Line

<u>Algebra I</u>

  • Range is the set of y-values that are outputted by function f(x)
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Step-by-step explanation:

<u>Step 1: Define</u>

[Relation] {(-4, 1), (-2, 0), (8, -1)}

<u>Step 2: Identify</u>

According to the relation, our y-values are 1, 0, and -1. These values would encompass our range.

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3 years ago
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