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3 years ago

in physical education class Sonia walks a distance of 0.12 Mile in one minute at the rate how far can she walk in 9 minutes

Mathematics

2 answers:

Snezhnost [94]3 years ago

5 0

She can walk 1.08 miles in 9 minutes

vampirchik [111]3 years ago

3 0

1.08 in 9 minutes total

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write a story problem that can be solved by finding the sum of 506,211 and 424,809. then solve the problem

Amiraneli [1.4K]

<u>Story Problem</u>

Mr. Bill Gates bought a house in Italy for $\$506,211$ and a house in Canada for $\$424,809$ . What is the total cost of the two houses?

we know that

The total cost is the sum of the cost each house

$\$506,211+\$424,809=\$931,020$

therefore

the answer is

The total cost is $\$931,020$

7 0

3 years ago

Read 2 more answers

A triangle has one angle measuring 3X degrees a second angle measures 2X +20°

Lena [83]

Answer : x = 20

Explanation :
3x + 2x +20 + 4x - 20 = 180

(3+2+4=9)

9x + 20 - 20
The 20s cancel each other out because one is positive and the other is negative

9x = 180

9x/9 = 180/9

X = 180 divided by 9

X = 20

7 0

3 years ago

The system of equations may have a unique solution, an infinite number of solutions, or no solution. Use matrices to find the ge

Leno4ka [110]

Answer:

Infinite number of solutions.

Step-by-step explanation:

We are given system of equations

$5x+4y+5z=-1$

$x+y+2z=1$

$2x+y-z=-3$

Firs we find determinant of system of equations

Let a matrix A= $\left[\begin{array}{ccc}5&4&5\\1&1&2\\2&1&-1\end{array}\right]$ and B= $\left[\begin{array}{ccc}-1\\1\\-3\end{array}\right]$

$\mid A\mid=\begin{vmatrix}5&4&5\\1&1&2\\2&1&-1\end{vmatrix}$

$\mid A\mid=5(-1-2)-4(-1-4)+5(1-2)=-15+20-5=0$

Determinant of given system of equation is zero therefore, the general solution of system of equation is many solution or no solution.

We are finding rank of matrix

Apply $R_1\rightarrow R_1-4R_2$ and $R_3\rightarrow R_3-2R_2$

$\left[\begin{array}{ccc}1&0&1\\1&1&2\\0&-1&-3\end{array}\right]$ : $\left[\begin{array}{ccc}-5\\1\\-5\end{array}\right]$

Apply $R_2\rightarrow R_2-R_1$

$\left[\begin{array}{ccc}1&0&1\\0&1&1\\0&-1&-3\end{array}\right]$ : $\left[\begin{array}{ccc}-5\\6\\-5\end{array}\right]$

Apply $R_3\rightarrow R_3+R_2$

$\left[\begin{array}{ccc}1&0&1\\0&1&1\\0&0&-2\end{array}\right]$ : $\left[\begin{array}{ccc}-5\\6\\1\end{array}\right]$

Apply $R_3\rightarrow- \frac{1}{2}$ and $R_2\rightarrow R_2-R_3$

$\left[\begin{array}{ccc}1&0&1\\0&1&0\\0&0&1\end{array}\right]$ : $\left[\begin{array}{ccc}-5\\\frac{13}{2}\\-\frac{1}{2}\end{array}\right]$

Apply $R_1\rightarrow R_1-R_3$

$\left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\end{array}\right]$ : $\left[\begin{array}{ccc}-\frac{9}{2}\\\frac{13}{2}\\-\frac{1}{2}\end{array}\right]$