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Sveta_85 [38]
3 years ago
14

Given a=4, b=-2 and c=8, evaluate a-b-c

Mathematics
1 answer:
atroni [7]3 years ago
8 0
Filling them in it would be ; 4 - (-2) - 8
And a negative against a negative equals a plus so ; 6 - 8 = your answer
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If t varies inversely as a and t= 2 when a = -4, what is t when a = 1/3?
bezimeni [28]

Answer:

t = - 24

Step-by-step explanation:

Given t varies inversely as a then the equation relating them is

t = \frac{k}{a} ← k is the constant of variation

To find k use the condition t = 2 when a = - 4

2 = \frac{k}{-4} ( multiply both sides by - 4 )

- 8 = k

t = \frac{-8}{a} ← equation of variation

When a = \frac{1}{3} , then

t = \frac{-8}{\frac{1}{3} } = - 24

5 0
3 years ago
GIVING BRAINLY JUST ANSWER CORRECTLY !!
Vinil7 [7]

Answer:

b. never

Explanation:

A fraction is always in the form p/q, where q is not 0; or can be converted in that form (in case of mixed fraction).

A number is said to be irrational, if it cannot be expressed in the form p/q, where q is not 0.

5 0
3 years ago
Triangle QST is isosceles, and Line segment R T bisects AngleT. Triangle Q S T is cut by bisector R T. The lengths of sides S T
Katyanochek1 [597]

Answer:

m∠QRT = 90°

m∠QRT = m∠SRT

Step-by-step explanation:

Triangle QST is isosceles with QT ≅ ST. In isoscels triangle QST, angles STR and RTQ are congruent.

RT is angle T bisector, so angles QTR and STR are congruent.

Consider two triangles QTR and STR. In these triangles:

  • TR ≅ TR (reflexive property);
  • ∠QTR ≅ ∠STR (given);
  • QT ≅ ST (given).

By SAS postulate, these two triangles are congruent. Two congruent triangles have congruent corresponding sides, so

  • QR ≅ SR
  • ∠QRT ≅ ∠SRT

Angles QRT and SRT are supplementary (add up to 180°). Since these two angles are congruent, they have the same measure equal to \frac{1}{2}\cdot 180^{\circ}=90^{\circ}

So, true options are

m∠QRT = 90°

m∠QRT = m∠SRT

7 0
4 years ago
Read 2 more answers
The diagram shows a right angled triangle use pythagoras theorem to work out length of side ac
Strike441 [17]

Answer:

Step-by-step explanation:

Using Pythagoras theorem,

AC^2 = AB^2 + BC^2

AC^2 = 4^2 + 15^2

AC^2 = 16 + 225

AC^2 = 241

AC = √241

4 0
4 years ago
To send a standard letter through First-Class mail, the cost depends on the weight of the letter. Any letter one ounce or less w
Hitman42 [59]

Answer:

Let x represents the total weight of the parcel and f(x) represents the cost of the parcel,

Then, according to the question,

Any letter one ounce or less will need $0.46 in postage.

That is, For 0 < x ≤ 1, f(x) = 0.46

For each additional ounce over that, or any part of an ounce, the sender must add $0.20 more postage,

Also, the maximum weight = 16 ounces,

0.46 + 0.20 (x-1)= 16

⇒ 0.20 (x-1) = 15.54

⇒ x-1 = 77.7⇒ x = 78.7

Hence, the function that shows the cost of the letter having weight greater than 1 ounces is,

And, for 1 < x ≤ 78.7 f(x) = 0.46 + 0.20(x-1),

Thus, the complete function that shows the given situation is,

f(x) = \begin{Bmatrix}0.46, & 0\leq x\leq1\\ 0.46+0.20(x-1) & 1

Thus, we get two line, y = 0.46 and y = 0.46 + 0.20(x-1),

Which are plotted in the below graph.

3 0
3 years ago
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