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PolarNik [594]
3 years ago
9

Which pair of rectangles is similar?​

Mathematics
2 answers:
tatuchka [14]3 years ago
6 0

c)

6/3 = 8/4 = 2

__________

MariettaO [177]3 years ago
5 0
The answer is C. When multiplying the smaller rectangle by 2 on both sides, you will get the bigger rectangle’s measurements
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Producing a musical costs $88,000 plus $5900 per performance. one sold out performance earns $7500 in revenue. If every performa
yan [13]
X = # of perfomances

y = total amount of money

Income: y = 7500x

Expense: y = 5900x + 88000



Substitution:

7500x = 5900x + 88000

1600x = 88000

x = 55

y = 7500(55) = $412,500

55 performances are needed to break-even.
5 0
3 years ago
Please help. Question is in the picture
kumpel [21]
Number 4: line XZ; number 5: theory of congruent triangles.
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3 years ago
What expression is equivalent to (4-x)+3
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The answer would be B
5 0
3 years ago
Find the equation of the line through (8,−6) which is perpendicular to the line y=x3−7.
ycow [4]

Answer:

y = (-1/3)(x + 10)

Step-by-step explanation:

The slope of the new (perpendicular) line is the negative reciprocal of the slope of the given line, which appears to be 3.  Thus, the perpendicular line has the slope -1/3.

Using the slope-intercept form y = mx + b, and substituting the givens, we obtain:

y = mx + b    =>    -6 = (-1/3)(8) + b, or

-6 = -8/3 + b.  We must solve for the y-intercept, b:

Multiplying all three terms by 3 removes the fraction:

-18 = -8 + 3b.  Thus, -10 = 3b, and so b must be -10/3.

The desired equation is    

y = (-1/3)x - 10/3, or

y = (-1/3)(x + 10)

8 0
3 years ago
Two athletic teams play a series of games; the first team to win 4 games is declared the overall winner. Suppose that one of the
kodGreya [7K]

Answer:

  • p=0.7103 (4-game series)
  • p=0.6480 (2-game series)

Step-by-step explanation:

Let X be the random variable equal the the first 4 straight wins. An overall win for the stronger team implies a negative binomial function with the parameters  n=4, p=0.6:

P(X=4)={{i-1}\choose {4-1}}0.6^40.4^{i-4},\  i=4,5,6,7

#We find probabilities for the different values of i:

P(X=4)={3\choose 3}0.6^4=0.1296\\\\P(X=5)={4\choose 3}0.6^40.4^1=0.2074\\\\P(X=6)={5\choose 3}0.6^40.4^2=0.2074\\\\P(X=4)={6\choose 3}0.6^40.4^3=0.1659

Hence, probability of the stronger team winning overall is:

=P(X=4)+P(X=5)+P(X=6)+P(X=7)\\\\=0.7103

#Define Y as the random variable for winning 2/3 games.:

P(Y=2)={1\choose 1}0.6^2=0.3600\\\\P(Y=3)={2\choose3}0.6^20.4=0.2880\\\\P(win)=0.2880+0.3600=0.6480

Hence, probability of the stronger team winning in 2 out 3 game series is 0.6480

The stronger team has a higher chance of winning in a 4-game series(0.7103>0.6480)

8 0
3 years ago
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