Select the correct answer from each drop-down menu. The possible values of x in the equation x^2-3/4 x=-1/4 are blank ± blank .

Mathematics

1 answer:

zlopas [31]3 years ago

8 0

Answer:

x = 3/8 +/- i(√5)/8.

Step-by-step explanation:

I can't see any list by this is the solution of the equation:

x^2 - 3/4x = -1/4

x^2 - 3/4 x + 1/4 = 0

Multiply by 4 to remove the fractions:

4x^2 - 3x + 1 = 0

x = [-(-3) +/- sqrt(3)^2 - 4*4*1)] / 8

x = 3/8 +/-√ (-5) / 8

x = 3/8 +/- √5 i / 8

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Consider functions f and g.1 + 12f(1) = 12 + 4. – 12for * # 2 and 7 -64.2 – 16. + 1641 +48for a # -12 Which expression is equal

lisabon 2012 [21]

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$\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}\text{ and} \\ g(x)=\frac{4x^2-16x+16}{4x+48} \end{gathered}$

Factorising the denominators of both functions,

Factorising the denominator of f(x),

$\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}=\frac{x+12}{x^2+6x-2x-12}=\frac{x+12}{x(x+6)-2(x+6)}=\frac{x+12}{(x-2)(x+6)} \\ f(x)=\frac{x+12}{(x-2)(x+6)} \end{gathered}$

Factorising the denominator of g(x),

$\begin{gathered} g(x)=\frac{4x^2-16x+16}{4x+48}=\frac{4(x^2-4x+4)}{4(x+12)} \\ \text{Cancel out 4 from both numerator and denominator} \\ g(x)=\frac{x^2-4x+4}{x+12}=\frac{x^2-2x-2x+4}{x+12}=\frac{x(x-2)-2(x-2)}{x+12}=\frac{(x-2)^2}{x+12} \\ g(x)=\frac{(x-2)^2}{x+12} \end{gathered}$

Multiplying both functions,