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3 years ago

Which statement is true? a. 82% < 1/7. b. 1/7 > 0.13. please help!!!

Mathematics

1 answer:

sergejj [24]3 years ago

5 0

B. 1/7 is greater than 0.13

1/7= 0.1428..

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What is three less than the product of four and the difference of a number and five

lilavasa [31]

Answer: 3-4n-5

Step-by-step explanation: 3-4 times an number-5 is 3-4n-5.

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3 years ago

Skylar and Rodrigo each recorded how far they traveled while skateboarding. Skylar traveled 65 feet in 5 seconds and Rodrigo tra

nikklg [1K]

9514 1404 393

Answer:

1/2 ft

Step-by-step explanation:

Skylar's speed was ...

(65 ft)/(5 s) = 13 ft/s

Rodrigo's speed was ...

(108 ft)/(8 s) = 13.5 ft/s

Rodrigo traveled farther by (13.5 -13) = 0.5 ft per second.

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3 years ago

Kyle spend 1/5 of his money on clothing. He had 120 remaining. What was the cost of the clothes Kyle bought

dolphi86 [110]

Answer:

30 is the cost of clothes Kyle bought.

Step-by-step explanation:

Given: Kyle spend 1/5 of his money on clothing.

Remaining money is 120.

Lets assume the total money Kyle had be "x".

∴ Money spent on clothes = $\frac{1}{5}\times x= \frac{x}{5}$

Now, putting up value in the equation to find the total amount of money.

We know, money remaining is 120

$x-\frac{x}{5} = 120$

Taking LCD subtract the fraction.

⇒ $\frac{(x\times 5)- x\times 1}{5} = 120$

⇒ $\frac{5x-x}{5} = 120$

⇒ $\frac{4x}{5} = 120$

Multiplying 5 both side

⇒ $4x= 120\times 5$

dividing 4 on both side.

∴ $x= \frac{120\times 5}{4}$

∴ x= 150

Kyle has total 150 money to spend.

Kyle spent $\frac{1}{5}$ of his total money on clothing.

⇒ cost of clothes kyle bought= $\frac{1}{5} \times 150= 30$

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6 0

3 years ago

Given the following coordinates complete the glide reflection transformation.

Romashka [77]

Answer:

$A" = (7,-2)$

$B" = (10,0)$

$C"= (12,-3)$

Step-by-step explanation:

Given

$A = (4,2)$

$B = (7,0)$

$C =(9,3)$

a: Reflect over x-axis

The rule of this is:

$(x,y) \to (x,-y)$

So, we have:

$A' = (4,-2)$

$B' = (7,0)$

$C' = (9,-3)$

b: Shift 3 units left

The rule of this is:

$(x,y) \to (x+3,y)$

So, we have:

$A" = (4+3,-2)$

$A" = (7,-2)$

$B" = (7+3,0)$

$B" = (10,0)$

$C"= (9+3,-3)$

$C"= (12,-3)$

4 0

3 years ago

Rearrange the equation so u is the independent variable.<br><br> -12u + 13 = 8w - 3<br><br> w = __

Flauer [41]

Answer:

the answer is -12u/3 + 2

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3 years ago

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