Ah yes, good ol’ Pythagorean’s theorem.
The hypotenuse is the opposite of the 90 degree angle, the longest side of the triangle.
The legs are opposite of the acute angles
Formula: a^2 + b^2 = c^2
2:
Let’s plug in some values
(6)^2 + (3)^2 = c^2
C = 6.7
The side will be 6.7 units
3)
Let’s plug in some values
(13.3)^2 = (9.7)^2 + (b)^2
(13.3)^2 - (9.7)^2 = b^2
176.89 - 94.09 = b^2
b = 9.1
The side will be 9.1 units
Answer:
the answer for this question is
10-1.125=71/8 or 8.875
= 9
Answer:
Distance between two points= √(x2-x1)²+(y2-y1)²
D= 15units
Let "k" be the y-coordinate of A
A(-6,k)
B(3,2)
15= √(3--6)²+(2-k)²
Taking square of both sides to eliminate the square root.
15²=(9)²+(2-k)²
225=81+4-4k+k²
k²-4k - 140=0
Using Quadratic Formula to evaluate
k= 14 or k=-10
The Possible coordinates of A are
(-6,14) or (-6,-10)
Answer:
Putting the value in x = 2 , y =4 in 2x - 2y we get,
2 × 2 - 4× 2= 4-8 = -4
Putting the value in z = 3 in z - 5 we get,
z - 5 = 3 - 5 = -2
Answer:
5.848 in
Step-by-step explanation:
Divide the piece of cardboard into nine equal squares of side z.
The centre square is the base of the cube.
When you cut out the corner squares and fold up the sides, you will have a cube with edge length z.
The cube must have a volume of 200 in³.
V = z³
200 = z³
![z = \sqrt[3]{200}](https://tex.z-dn.net/?f=z%20%3D%20%5Csqrt%5B3%5D%7B200%7D)
![z = \sqrt[3]{8\times25}](https://tex.z-dn.net/?f=z%20%3D%20%5Csqrt%5B3%5D%7B8%5Ctimes25%7D)
![z = 2\sqrt[3]{25}](https://tex.z-dn.net/?f=z%20%3D%202%5Csqrt%5B3%5D%7B25%7D)
z = 2 × 2.924
z = 5.848 in
The edge length of the cube is 5.848 in.
