!!!!HELP NEEDED!!!!
1 answer:
It is true that the product of two consecutive even integers are always one less than the square of their average.
<u>Step-by-step explanation</u>:
Let the two consecutive odd integers be 1 and 3.
- The product of 1 and 3 is (1
3)=3
- The average of 1 and 3 is (1+3)/2 =4/2 = 2
- The square of their average is (2)² = 4
∴ The product 3 is one less than the square of their average 4.
Let the two consecutive even integers be 2 and 4.
- The product of 2 and 4 is (2
- The average of 2 and 4 is (2+4)/2 =6/2 = 3
- The square of their average is (3)² = 9
∴ The product 8 is one less than the square of their average 9.
Thus, It is true that the product of two consecutive even integers are always one less than the square of their average.
You might be interested in
Answer:
Sum of money invested in corporate bonds = 30,000
Step-by-step explanation:
Total sum = 40,000
The rate of interest for corporate bonds = 10 % = 0.1
The rate of interest for municipal bonds = 6 % = 0.06
Total interest = 3600
Let sum of money invested in corporate bonds = x
The sum of money invested in municipal bonds = 40000 - x
× 0.1 × 1 + (
) × 0.06 × 1 = 3600
(0.1- 0.06) + 2400 = 3600
0.04 = 1200
= 30,000
Since x = sum of money invested in corporate bonds
So sum of money invested in corporate bonds = 30000
The ODE is separable, i.e. you can write
Integrating both sides gives the general solution.
Given that
, we have
and so the particular solution to the IVP is
Integrating both sides gives the general solution.
Given that
and so the particular solution to the IVP is