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3 years ago

Can someone help me please????

Mathematics

1 answer:

lapo4ka [179]3 years ago

3 0

Answer:

330; 2

Step-by-step explanation:

The total number of patients was 330.

There were two days when more than 28 patients visited the clinic.

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F(x)=2x^2-x-6 g(x)=4-x (f+g)(x)

Semenov [28]

$\large \boxed{(f + g)(x) = f(x) + g(x)}$

The property above is distribution property where we distribute x-term in the function.

Substitute both f(x) and g(x) in.

$\large{ \begin{cases} f(x) = 2 {x}^{2} - x - 6 \\ g(x) = 4 - x \end{cases}} \\ \large{f(x) + g(x) = (2 {x}^{2} - x - 6) + (4 - x)} \\ \large{f(x) + g(x) = 2 {x}^{2} - x - 6 + 4 - x}$

Évaluate/Combine like terms.

$\large{f(x) + g(x) = 2 {x}^{2} - 2x - 2}$

The function can be factored so there are two answers. (Both of them work as one of them is factored form while the other one is not.)

$\large{(f + g)(x) = 2 {x}^{2} -2x -2}$

<u>Alternative</u>

$\large{(f + g)(x) = 2({x}^{2} -x - 1)}$

<u>Answer</u>

(f+g)(x) = 2x²-2x-2
(f+g)(x) = 2(x²-x-1)

Both answers work. The second answer is in factored form.

Let me know if you have any doubts!

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Rachel prepared 24 kilograms of dough after working 6 hours. How

attashe74 [19]

Answer:

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