Question 1)
Given: F(x) = 3x^2 + 1, G(x) = 2x - 3, H(x) = x
F(G(x)) = 3(2x - 3)^2 + 1
F(G(x)) =3(4x^2 - 12x + 9) + 1
F(G(x)) = 12x^2 - 36x + 27 + 1
F(G(x)) =12x^2 - 36x + 28
Question 2)
H -1 (x) = x (inverse)
Answer:
Step-by-step explanation:
2s + t = r
t = r - 2s
It is the number 3.
w-10=2(w+5)
w-10=2w+10
w-2w=10+10
-w=20
w=-20