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3 years ago

A quarter throws a football from a height of 6.5 feet with an initial velocity of 64 feet per second

Mathematics

1 answer:

ohaa [14]3 years ago

8 0

Answer:

0.10s

Step-by-step explanation:

Given data

DIstance= 6.5ft

velocity = 64 feet per second

with the parameters given above, we can find the time taken as

velocity = distance/time

time= distance/velocity

time= 6.5/64

time= 0.10 seconds

Hence the time the ball took is 0.10s

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Multiply the complex numbers (5 − 3i) and (9 + 2i).

amid [387]

The answer is

51-17i

Explanation :

5x95x2i-3ix9-3ix2i
45+10i-27i-6^2
45+10i-27i-6(-1)
45+10i-27i + 6

7 0

3 years ago

3× - 4y =65 when u =4

sergey [27]

If Y=4 then X=27
hope this helps

8 0

3 years ago

Read 2 more answers

What is the multiplicative rate of change of the exponential function shown on the graph? Two-ninths 1 4 Nine-halves

sattari [20]

Answer:

The answer is nine-halves, the last option.

5 0

3 years ago

Find the value of x. 8,13,x

yawa3891 [41]

Answer:

x=18

Step-by-step explanation:

Key skills needed: Arithmetic Sequences, Addition

1) We have a sequence of 8,13,x

2) To find the number being added every time, we do 13-8. This is 5.

3) This means x would be 13+5

4) 13+5 is 18 so x is 18.

Hope you understood and have a nice day!! :D

8 0

3 years ago

Find the area of following rhombuses. Round your answers to the nearest tenth if necessary.

polet [3.4K]

Answer:

$Area =55.4ft^2$

Step-by-step explanation:

Given

The attached rhombus

Required

The area

First, calculate the length of half the vertical diagonal (x).

Length x is represented as the adjacent to 60 degrees

So, we have:

$\tan(60) = \frac{4\sqrt 3}{x}$

Solve for x

$x = \frac{4\sqrt 3}{\tan(60)}$

$\tan(60) = \sqrt 3$

So:

$x = \frac{4\sqrt 3}{\sqrt 3}$

$x = 4$

At this point, we have established that the rhombus is made up 4 triangles of the following dimensions

$Base = 4\sqrt 3$

$Height = 4$

So, the area of the rhombus is 4 times the area of 1 triangle

$Area = 4 * \frac{1}{2} * Base * Height$

$Area = 4 * \frac{1}{2} * 4\sqrt 3 * 4$

$Area =2 * 4\sqrt 3 * 4$

$Area =55.4ft^2$

7 0

3 years ago