Answer:
I need the options mate to chose which is correct
Step-by-step explanation:
First, you find how many total feet Rick can afford. To do this, you do 2000/20 which equals 100. Then, you write your inequality. 100 is less than or equal to 2x+6. Next, you solve your inequality. You subtract 6 on both sides to get 94 equals 2x. To solve this, you divide by 2 on both sides. In this scenario, x stands for the width.
Answer:
Less than 100. Z=83
Step-by-step explanation:
The mean is the average found by adding the sum of the data points and dividing by the number of them. Here there are 3 cars whose speeds are 101, 116, and Z or unknown. The mean of them is 100. Solve for Z.
100 =(101+116+Z)/3
300=217+Z
83=Z
Answer:
Yes, double cosets partition G.
Step-by-step explanation:
We are going to define a <em>relation</em> over the elements of G.
Let 
. We say that 
if, and only if, 
, or, equivalently, if 
, for some 
.
This defines an <em>equivalence relation over </em><em>G</em>, that is, this relation is <em>reflexive, symmetric and transitive:</em>
- Reflexivity: (
for all 
.) Note that we can write 
, where 
is the <em>identity element</em>, so 
and then 
. Therefore, . - Symmetry: (If then
.) If then 
for some 
and 
. Multiplying by the inverses of h and k we get that 
and is known that 
and 
. This means that 
or, equivalently, .
- Transitivity: (If and
, then 
.) If and , then there exists 
and 
such that 
and 
. Then, 
where 
and 
. Consequently, 
.
Now that we prove that the relation "
" is an equivalence over G, we use the fact that the <em>different equivalence classes partition </em><em>G.</em><em> </em>Since the equivalence classes are defined by ![[x]=\{y\in G\colon x\sim y\} =\{y\in G \colon y=hgk\ \text{for some } h\in H, k\in K \}=HxK](https://tex.z-dn.net/?f=%5Bx%5D%3D%5C%7By%5Cin%20G%5Ccolon%20x%5Csim%20y%5C%7D%20%3D%5C%7By%5Cin%20G%20%5Ccolon%20y%3Dhgk%5C%20%5Ctext%7Bfor%20some%20%7D%20h%5Cin%20H%2C%20k%5Cin%20K%20%5C%7D%3DHxK)
, then we're done.
