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QveST [7]
3 years ago
13

You pick 4 digits (0-9) at random without replacement, and write them in the order picked. what is the probability that you have

written the first 4 digits of your phone number? assume there are no repeats of digits in your phone number.
Mathematics
1 answer:
Sophie [7]3 years ago
7 0

The number of ways of choosing 4 digits from 10 digits without replacement ( order is important) is P(10,4)=\frac{10!}{(10-4)!} =\frac{10!}{(6)!} =7*8*9*10=5040. This is the number of all possible permutations of choosing 4 from 10. The first 4 numbers of your phone number is a unique 4 digit number(4 different digits). The required probability is

\frac{1}{5040}

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Pleaseee help!
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Step-by-step explanation:

f(3)=?

f(x)=2x+5

put x=3,

f(3)=2(3)+5=6+5=11

------------

g(2)=?

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put x=2,

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-----------------

g(f(-1))=?

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and f(-1)=2(-1)+5= -2+5=3

so g(f(-1))=3^2-3=9-3=6

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f(g(-1))=?

f(x)=2x+5

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f(g(-1))=2(-2)+5= -4+5=1

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g(f(x))=?

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put x=f(x),

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7 0
3 years ago
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Verdich [7]
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Explanation

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3 years ago
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