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QveST [7]
3 years ago
13

You pick 4 digits (0-9) at random without replacement, and write them in the order picked. what is the probability that you have

written the first 4 digits of your phone number? assume there are no repeats of digits in your phone number.
Mathematics
1 answer:
Sophie [7]3 years ago
7 0

The number of ways of choosing 4 digits from 10 digits without replacement ( order is important) is P(10,4)=\frac{10!}{(10-4)!} =\frac{10!}{(6)!} =7*8*9*10=5040. This is the number of all possible permutations of choosing 4 from 10. The first 4 numbers of your phone number is a unique 4 digit number(4 different digits). The required probability is

\frac{1}{5040}

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Need help on the last problem please.
pshichka [43]

Answer:

6 of x and 5 of y

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x = number of closets of the first type

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erastova [34]
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8 0
3 years ago
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Yuliya22 [10]

Answer:

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Step-by-step explanation:

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Step 3: Use subtraction property of equality:

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3 years ago
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pishuonlain [190]
\boxed{ \frac{500}{6.7} = 74.627\ Answer}
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