To answer the question, you need to determine the amount Mr. Traeger has left to spend, then find the maximum number of outfits that will cost less than that remaining amount.
Spent so far:
... 273.98 + 3×7.23 +42.36 = 338.03
Remaining available funds:
... 500.00 -338.03 = 161.97
The cycling outfits are about $80 (slightly less), and this amount is about $160 (slightly more), which is 2 × $80.
Mr. Traeger can buy two (2) cycling outfits with the remaining money.
_____
The remaining money is 161.97/78.12 = 2.0733 times the cost of a cycling outfit. We're sure he has no interest in purchasing a fraction of an outfit, so he can afford to buy 2 outfits.
Answer:
13) 25 and 17
14) cupcakes = $5
brownies = $3
Step-by-step explanation:
13) you can set this up as equations
so x + y = 42
x-y = 8
solve simultaneously by subtracting from each other
2y = 34
y= 17
if y = 17
42 - 17 = 25 = x
14) set up as equations again
Ben 7c + 10b = 65
franklin 7c +7b = 56
subtract from eachother
3b = 9
b = $3
7c + 10(3) = 65
7c = 35
c = $5
Answer:
5 × a + b
Step-by-step explanation:
Product = Multiply
Sum = Addition
5 times a
5 × a + b
Hope this helps! <3
Answer: <em>4</em> i think :)
Answer: 14/11
Step-by-step explanation:
When 14/11 is multiplied by 1/4, you get a repeating decimal. All repeating decimals are rational.
Hope it helps <3
