Answer:
D?
Step-by-step explanation:
I think it is D since a universal set would only be {1,2,3,4,5,6,...} and the subset would not satisfy any of the conditions of symmetric, transitive, and reflexive.
Yes it is the same. 1/4 +1/4 = 1/2. so 9/10-1/2=9/10-1/2
(not <em>a</em> or not <em>b</em>) implies <em>c</em> <==> not (not <em>a</em> or not <em>b</em>) or <em>c</em>
so negating gives
not [(not <em>a</em> or not <em>b</em>) implies <em>c</em>] <==> not[ not (not <em>a</em> or not <em>b</em>) or <em>c</em>]
which we can simplify somewhat to
not (not (not <em>a</em> or not <em>b</em>)) and not <em>c</em>
(not <em>a</em> or not <em>b</em>) and not <em>c</em>
(not <em>a</em> and not <em>c</em>) or (not <em>b</em> and not <em>c</em>)
not (<em>a</em> or <em>c</em>) or not (<em>b</em> or <em>c</em>)
not ((<em>a</em> or <em>c</em>) and (<em>b</em> or <em>c</em>))
not ((<em>a</em> and <em>b</em>) or <em>c</em>)
Answer:
4.5=9+8=10 cause we subbed
8+9=17
Step-by-step explanation:
Answer:
235 cm²
Step-by-step explanation:
Find area of the large rectangle on the bottom. To do that, find its length and width, then multiply them together.
Length of big rectangle=20 cm
Width of big rectangle=9 cm
20x9=180 cm²
Next, find the area of the small rectangle on the top. To do that, find its length and width, then multiply them together.
Length of small rectangle=11 cm
Width of small rectangle=5 cm
I found the width by subtracting 9 from 14, since the 9 cm is part of the large rectangle.
11x5=55 cm²
Add the areas of the two rectangles.
55+180=235 cm²
