Answer:c
Step-by-step explanation:c
Answer:when x = -11
2×11-19=22-19
=3
Step-by-step explanation:
Answer: 56
Step-by-step explanation:
Let x be the number that is supposed to be subtracted from 61.
Given
61 - x = 5
Add both sides by x
61 - x + x = 5 + x
61 = 5 + x
Subtract 5 on both sides
61 - 5 = 5 + x - 5
x = 56
Hope this helps!! :)
Please let me know if you have any questions
![(2)\text{ }\sqrt[]{130}](https://tex.z-dn.net/?f=%282%29%5Ctext%7B%20%7D%5Csqrt%5B%5D%7B130%7D)
Explanation
to solve this we can use the distance between 2 points formula:
![\begin{gathered} D_{12}=\sqrt[]{(x_2_{}-x_1)^2+(y_2-y_1)^2} \\ whereP1(x_1,y_1)\text{ is the initial point} \\ \text{and P}_2\text{ is the end point} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20D_%7B12%7D%3D%5Csqrt%5B%5D%7B%28x_2_%7B%7D-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D%20%5C%5C%20whereP1%28x_1%2Cy_1%29%5Ctext%7B%20is%20the%20initial%20point%7D%20%5C%5C%20%5Ctext%7Band%20P%7D_2%5Ctext%7B%20is%20the%20end%20point%7D%20%5Cend%7Bgathered%7D)
then,Let
Initial point= A=(0,7)
end point= B=(9,0)
now, replace in the formula
![\begin{gathered} D_{12}=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2} \\ D_{AB}=\sqrt[]{(9-0)^2+(0-7)^2} \\ D_{AB}=\sqrt[]{(9)^2+(-7)^2} \\ D_{AB}=\sqrt[]{81+49^{}} \\ D_{AB}=\sqrt[]{130} \\ \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20D_%7B12%7D%3D%5Csqrt%5B%5D%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D%20%5C%5C%20D_%7BAB%7D%3D%5Csqrt%5B%5D%7B%289-0%29%5E2%2B%280-7%29%5E2%7D%20%5C%5C%20D_%7BAB%7D%3D%5Csqrt%5B%5D%7B%289%29%5E2%2B%28-7%29%5E2%7D%20%5C%5C%20D_%7BAB%7D%3D%5Csqrt%5B%5D%7B81%2B49%5E%7B%7D%7D%20%5C%5C%20D_%7BAB%7D%3D%5Csqrt%5B%5D%7B130%7D%20%5C%5C%20%20%5Cend%7Bgathered%7D)
so, the answer is
I hope this helps you
Answer:
1 is 55
2 is 128
3 is 175
4 is no because the sell price is not 12 dollars, its 12 dollars extra
5 is A
Step-by-step explanation:
