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3 years ago

3x + y=11 -2x + y=1 Solve using substitution method

Mathematics

2 answers:

Alja [10]3 years ago

8 0

Step-by-step explanation:

here's the solution : -

=》3x + y = 11

=》y = 11 - 3x

now, plugging the value of y in equation 2

=》-2x + y = 1

=》-2x + 11 - 3x = 1

=》-5x = -10

=》x = 2

now, plugging the value of x as 2 in equation 1

=》3x + y = 11

=》6 + y = 11

=》y = 11 - 6

=》y = 5

nata0808 [166]3 years ago

6 0

Answer:

3x+yl=11

-2x+y=11

y=11-3x

-2x+11-3x=11

-5x=11-11

so x=0

y=11-0

y=11

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Katena32 [7]

Answer:

(a)

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(b)

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(c)

$(-5^{-3})^{-1}=-125$

(d)

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Step-by-step explanation:

(a)

$5^{-3}$

we can use property of exponent

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we get

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(b)

$-5^{-3}$

we can use property of exponent

$a^{-n}=\frac{1}{a^n}$

we get

$-5^{-3}=-\frac{1}{5^3}$

$-5^{-3}=-\frac{1}{5\times 5\times 5}$

$-5^{-3}=-\frac{1}{125}$ ........Answer

(c)

$(-5^{-3})^{-1}$

we can use property of exponent

$(a^{n})^m=a^{m\times n}$

we get

$(-5^{-3})^{-1}=(-5)^{-3\times -1}$

$(-5^{-3})^{-1}=(-5)^3$

$(-5^{-3})^{-1}=(-5)\times (-5)\times (-5)$

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(d)

$(-5^{-3})^{0}$

we can use property of exponent

$(a^{n})^m=a^{m\times n}$

we get

$(-5^{-3})^{0}=(-5)^{-3\times 0}$

$(-5^{-3})^{-1}=(-5)^0$

we can use property

$a^0=1$

$(-5^{-3})^{0}=1$ ........Answer

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