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dlinn [17]
4 years ago
6

Depreciation is the process of:

Business
1 answer:
Lana71 [14]4 years ago
4 0

Answer:

The answer is c. allocating the cost of an asset to expense over its useful life in a rational and systematic manner.

Explanation:

Depreciation is an accounting method of allocating the cost of a tangible or physical asset over its useful life or life expectancy.

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What are 3 helpful habits (to prepare for a big test)?<br><br> Plz be specific.
Alenkinab [10]
Hello!

Here are some tips:

• Get a good night's sleep. Believe me, if I don't get at least 7 hours of sleep before a big test, my mind won't function properly and I'll forget everything I'd practised. So, please, get enough sleep.

• Eat something good before the test. It'll help you. When your belly is full, almost everything is okay! :D Seriously, eat enough so that you wouldn't get hungry during the test, and you'll have less to think about. Also, make sure the food doesn't contain too much sugar.

• Take breaks when you're studying. Do NOT cram all those facts in your head, because they won't stay there. Set up a schedule and designate a specific part of every day to studying, and it shouldn't be longer than half an hour.

• Here's a bonus tip I've learned from past experiences. Please don't use TVs, phones, and anything that will distract you. If you need a calculator, USE A CALCULATOR, and not an online one. Otherwise you won't be as productive and it'll definitely distract you.
6 0
3 years ago
Read 2 more answers
Weston's uses stralght-line depreclation to zero over a project's life. A new project has a fixed asset cost of $2,687,300 and p
nexus9112 [7]

Answer:

D) 15.76 percent

Explanation:

First, sum up the expected cash inflows;

= (95,000 + 162,000 + 286,000 + 304,000)

= 847,000

Next, find average cash inflows by dividing 847,000 by 4 years;

= 847,000/4

= 211,750

Initial amount invested = 2,687,300

Find the average amount by dividing 2,687,300 by 2

= 2,687,300/2

= 1,343,650

To find average accounting return, divide 211,750 by 1,343,650;

= 211,750 / 1,343,650

= 0.15759

As a percentage, it becomes 15.76%

4 0
4 years ago
Earl and Mary form Crow Corporation. Earl transfers property, basis of $200,000 and value of $1,600,000, for 50 shares in Crow C
barxatty [35]

Answer: The correct answer is "c.Crow will have a business deduction of $120,000 for the value of the services Mary will render.".

Explanation: With respect to the transfers: Crow will have a business deduction of $120,000 for the value of the services Mary will render.

This is calculated by the difference between the value of the property contributed by Earl $1 600 000 and the value of the property contributed by Mary $1 480 000.

1 600 000 - 1 480 000 = $ 120 000.

4 0
4 years ago
For Bonita Industries at a sales level of 4000 units, sales is $69000, variable expenses total $46000, and fixed expenses are $2
Marysya12 [62]

Answer:

the contribution margin per unit is $5.75 per unit

Explanation:

The computation of the contribution margin per unit is shown below:

The Contribution margin per unit is

Contribution margin per unit= Contribution margin ÷ Sales units

= ($69,000 - $46,000 ) ÷ 4,000

= $5.75 per unit

Hence, the contribution margin per unit is $5.75 per unit

We simply applied the above formula so that the correct value could come

And, the same is to be considered

7 0
3 years ago
In an Argand diagram, the point P represents the complex number z, where z = x + iy. Given that z + 2 = λi(z + 8), where λ is a
Scilla [17]

Answer:

The answer is   "\boxed{z= \frac{-16}{5}- \frac{-12}{15}i}".

Explanation:

As the problem stands  

At the point of P, it is the complex number z in the Diagram of Argand and z = X+iy.  

We have said this: (z+2)= \lambda i (z +8) .... (i)

where the \lambda parameter is a true  

The conceptual equation of the locus P varies between z = x+iy  \ \ \ to \ \ \ \lambda

And in equation mentioned above.

x+iy+2=\lambda i(x+iy+8) \\\\x+iy+2= \lambda xi+ \lambda i^2y+\lambda 8i\\\\ x+2+iy=-y \lambda +i(x+8)\lambda\\\ compare \ real \ and \ imaginary\  part \\\\\ x+2 = -y\lambda \\\\y= (x+8) \lambda\\\\   \lambda  = \frac{x+2}{-y}  \\ \\ \lambda = \frac{y}{x+8}

y^2= -x^2-10x-16 ....(ii)\\\\z= \mu (4+3i)....(iii)\\\\\ z= x+iy \\\\x+iy = 4\mu + 3 \mu i \\\\x= 4\mu \\\\y= 3\mu

put the value of x, y  in equation (ii) we get:

5\mu +4=0\\\\\mu = \frac{-4}{5} \\\\

to put the of \mu in equation (iii) we get:

z= \frac{-4}{5} (4+3i) \\\\ \boxed{z= \frac{-16}{5}- \frac{-12}{15}i} \\

8 0
4 years ago
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