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spayn [35]
4 years ago
13

How would I solve (6r +3)2 and show my work?

Mathematics
1 answer:
Eddi Din [679]4 years ago
4 0

Answer:

12r+6

Step-by-step explanation:

2(6r+3)

2(6r)+2(3)

12r+6

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Can i have some help
Marina CMI [18]
For 1. If two lines are parallel, the slopes are the same.
If two lines are perpendicular, the slopes are the opposite reciprocal, or is -1.
2. The answer is 3/2. Because in a perpendicular slope of a line, it has to be opposite sign and the reciprocal.
3.It is parallel.
because first we solve 6x-3y=8
We move the 6x to the other side, making it -6x
Now we have -3y=-6x+8
We use the y=Mx+b
-3y=-6x+8
Then we divide by -3
answer: y= 2x-8/3
now compare
y=2x+3
and
y=2x-8/3
With this we know it’s parallel because it’s the same slope but different y-intercept .

-I hope I helped:,)
4 0
3 years ago
How to write 10-3 two ways
nydimaria [60]
12-5=7
13-6=7
or if you were doing fractions
ten thirds
3
-
10
5 0
3 years ago
translate in an algebraic expression: 15 less a number t is four more than the sum of seven and t divided by two
aniked [119]
T - 15 = [(7 + t)/2] + 4
5 0
3 years ago
If angle 3 is 3x and angle 5 is 2x+30, what are the measures of angle 3 and 5?
Crank

Answer:

23

Step-by-step explanation:

5 0
3 years ago
HELP 100 POINTS .........SHOW YOUR WORK
Bas_tet [7]
Using Pythagorean theorem

x^2 + 6^2 = sqrt(117)^2

x^2 + 36 = 117

x^2 = 117 -36
x^2 = 81

x = sqrt(81)
x = 9
 
3 0
3 years ago
Read 2 more answers
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