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nadya68 [22]
2 years ago
5

A group of students were surveyed to find out if they like watching television or reading during their free time. The results of

the survey are shown below:
90 students like watching television
20 students like watching television but do not like reading
80 students like reading
40 students do not like watching television
Make a two-way table to represent the data and use the table to answer the following questions.
Part A: What percentage of the total students surveyed like both watching television and reading? Show your work. (5 points)
Part B: What is the probability that a student who does not like watching television also does not like reading? Explain your answer. (5 points)
Mathematics
1 answer:
rjkz [21]2 years ago
5 0

Answer:

110/170 = 0.6471 = 64.7% or 65%

Step-by-step explanation:

                              reading |   television

Television          |    70        |    20        |        90 total for TV

___________________________________________________

Reading             |    40        |    40         |       80 total for reading

___________________________________________________

Total students   |    110        |      60       |        170 total students

Students who like BOTH are 70 + 40 = 110   percentage = part/whole = 110/170

Students who ONLY like television = 20

Students who ONLY like reading = 40

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F(x) = x3 – 4x² - 6x – 32 at x = 6
scoundrel [369]

Answer:

X= 140

Step-by-step explanation:

f(x) = x3 – 4x² - 6x – 32 at x = 6

(6)(6)(6) -4²=72

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3 0
3 years ago
Based on past experience, a telemarketing firm has found that calls to prospective customers take an average of 2.0 minutes, wit
xenn [34]

Answer: Our required probability would be 0.9641.

Step-by-step explanation:

Since we have given that

Number of hours he works a day = 8

So, Number of minutes he worked in a day = 8\times 60=480\ minutes

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So, Average =\bar{x}=\dfrac{480}{220}=2.18\ minutes

Standard deviation =s=\dfrac{\sigma}{\sqrt{n}}=\dfrac{1.5}{\sqrt{220}}=0.10

Mean = μ = 2.0 minutes

Standard deviation = σ = 1.5 minutes

Using the normal distribution, we get that

z=\dfrac{\bar{x}-\mu}{s}\\\\z=\dfrac{2.18-2.0}{0.10}\\\\z=1.8

So, the probability that Albert will meet or exceed his quota would be

P(X\leq 2.18)=P(z\leq 1.8)=0.9641

Hence, our required probability would be 0.9641.

6 0
3 years ago
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Answer:

1/3

Step-by-step explanation:

for every 1 part of water there is 3 parts juice so if there's only 1 part juice it would be a 1/3

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2 years ago
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Step-by-step explanation:

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