<span><span>C=(<span>x0</span>,<span>y0</span>,<span>z0</span>)</span><span>C=(<span>x0</span>,<span>y0</span>,<span>z0</span>)</span></span><span> and radius </span><span>rr</span>.
<span><span>(x−<span>x0</span><span>)2</span>+(y−<span>y0</span><span>)2</span>+(z−<span>z0</span><span>)2</span>=<span>r2</span></span><span>(x−<span>x0</span><span>)2</span>+(y−<span>y0</span><span>)2</span>+(z−<span>z0</span><span>)2</span>=<span>r2</span></span></span><span> </span>
2000$ -637$=1363
But that is what I think not saying its wrong
Answer:
They will be able to sell 28 vases, with none left over.
Step-by-step explanation:
We do 14x12, since it is 14 dozens. It is 168. Then we divide by six since there are 6 roses in each vase. We get 28 with no remainders, meaning there are none left over.
Answer:
The approximate percentage of women with platelet counts within 3 standard deviations of the mean is 99.7%.
Step-by-step explanation:
We are given that the blood platelet counts of a group of women have a bell-shaped distribution with a mean of 247.3 and a standard deviation of 60.7.
Let X = <em>t</em><u><em>he blood platelet counts of a group of women</em></u>
The z-score probability distribution for the normal distribution is given by;
Z = ~ N(0,1)
where, = population mean = 247.3
= standard deviation = 60.7
Now, according to the empirical rule;
- 68% of the data values lie within one standard deviation of the mean.
- 95% of the data values lie within two standard deviations of the mean.
- 99.7% of the data values lie within three standard deviations of the mean.
Since it is stated that we have to calculate the approximate percentage of women with platelet counts within 3 standard deviations of the mean, or between 65.2 and 429.4, i.e;
z-score for 65.2 =
= = -3
z-score for 429.4 =
= = 3
So, it means that the approximate percentage of women with platelet counts within 3 standard deviations of the mean is 99.7%.