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rodikova [14]
3 years ago
9

fills an aquarium to a depth of 3/4 meters in 2 2/5 minutes what is the unit rate in minutes per meter

Mathematics
1 answer:
Kisachek [45]3 years ago
6 0

Answer:

 3 1/5 minutes per meter

Step-by-step explanation:

To find the rate in minutes per meter, divide the number of minutes by the number of meters:

  (2.4 min)/(0.75 m) = 3.2 min/m = 3 1/5 minutes per meter

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Identify the sequence as arithmetic, geometric, or neither. Explain your answer.
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This sequence (1.6, 0.8, 0.4, 0.2,... ) is geometric.
We have formula for any member of geometric sequence: a_{n} = a_{1}* q^{n-1} If a1=1.6 then:0.8=1.6*q, 0.4=1.6* q^{2}, 0.2=1.6* q^{3}The solution for all these equations is: q=0.5. We have: a1=1.6, q=0.5 and this is geometric sequence.
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On the coordinate plane below, quadrilaterals TRAP and HELP are similar to each other.
Aleks04 [339]

Answer:Quadrilateral TRAP has an area that is one-fourth the area of quadrilateral

Step-by-step explanation:

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3 years ago
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\dfrac{1}{3^{-2}x^{-4}y^2}=\dfrac{3^2x^4}{y^2}\\\\\\
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Answer B)
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3 years ago
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The sugar content of the syrup in canned peaches is normally distributed. A random sample of n = 10 cans yields a sample standar
Serggg [28]

Answer:

The 95% confidence interval is given by:

3.30<σ<8.76

Step-by-step explanation:

1) Data given and notation

s=4.798 represent the sample standard deviation

\bar x represent the sample mean

n=10 the sample size

Confidence=95% or 0.95

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population mean or variance lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.

The Chi Square distribution is the distribution of the sum of squared standard normal deviates .

2) Calculating the confidence interval

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

df=n-1=10-1=9

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a tabel to find the critical values.  

The excel commands would be: "=CHISQ.INV(0.025,9)" "=CHISQ.INV(0.975,9)". so for this case the critical values are:

\chi^2_{\alpha/2}=19.022

\chi^2_{1- \alpha/2}=2.700

And replacing into the formula for the interval we got:

\frac{(9)(4.798)^2}{19.022} \leq \sigma \frac{(9)(4.798)^2}{2.700}

10.892 \leq \sigma^2 \leq 76.736

Now we just take square root on both sides of the interval and we got:

3.30 \leq \sigma \leq 8.76

So the best option would be:

3.30<σ<8.76

7 0
3 years ago
Which conditions will result in the construction of a unique triangle?
Arlecino [84]

Answer:

A unique triangle will be produced if you are given: all three sides (Side-Side-Side) two sides and the included angle (Side-Angle-Side) two angles and the included side (Angle-Side-Angle)

Step-by-step explanation:

oof sorry I barely realized that I was supposed to select a number....sorry, but hope this helps :)

3 0
2 years ago
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