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4 years ago

2 Points

Mathematics

1 answer:

Crazy boy [7]4 years ago

7 0

The correct answer is d

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How to solve part ii and iii

iragen [17]

(i) Given that

$\tan^{-1}(x) + \tan^{-1}(y) + \tan^{-1}(xy) = \dfrac{7\pi}{12}$

when $x=1$ this reduces to

$\tan^{-1}(1) + 2 \tan^{-1}(y) = \dfrac{7\pi}{12}$

$\dfrac\pi4 + 2 \tan^{-1}(y) = \dfrac{7\pi}{12}$

$2 \tan^{-1}(y) = \dfrac\pi3$

$\tan^{-1}(y) = \dfrac\pi6$

$\tan\left(\tan^{-1}(y)\right) = \tan\left(\dfrac\pi6\right)$

$\implies \boxed{y = \dfrac1{\sqrt3}}$

(ii) Differentiate $\tan^{-1}(xy)$ implicitly with respect to $x$ . By the chain and product rules,

$\dfrac d{dx} \tan^{-1}(xy) = \dfrac1{1+(xy)^2} \times \dfrac d{dx}xy = \boxed{\dfrac{y + x\frac{dy}{dx}}{1 + x^2y^2}}$

(iii) Differentiating both sides of the given equation leads to

$\dfrac1{1+x^2} + \dfrac1{1+y^2} \dfrac{dy}{dx} + \dfrac{y + x\frac{dy}{dx}}{1+x^2y^2} = 0$

where we use the result from (ii) for the derivative of $\tan^{-1}(xy)$ .

Solve for $\frac{dy}{dx}$ :

$\dfrac1{1+x^2} + \left(\dfrac1{1+y^2} + \dfrac x{1+x^2y^2}\right) \dfrac{dy}{dx} + \dfrac y{1+x^2y^2} = 0$

$\left(\dfrac1{1+y^2} + \dfrac x{1+x^2y^2}\right) \dfrac{dy}{dx} = -\left(\dfrac1{1+x^2} + \dfrac y{1+x^2y^2}\right)$

$\dfrac{1+x^2y^2 + x(1+y^2)}{(1+y^2)(1+x^2y^2)} \dfrac{dy}{dx} = - \dfrac{1+x^2y^2 + y(1+x^2)}{(1+x^2)(1+x^2y^2)}$

$\implies \dfrac{dy}{dx} = - \dfrac{(1 + x^2y^2 + y + x^2y) (1 + y^2) (1 + x^2y^2)}{(1 + x^2y^2 + x + xy^2) (1+x^2) (1+x^2y^2)}$

$\implies \dfrac{dy}{dx} = -\dfrac{(1 + x^2y^2 + y + x^2y) (1 + y^2)}{(1 + x^2y^2 + x + xy^2) (1+x^2)}$

From part (i), we have $x=1$ and $y=\frac1{\sqrt3}$ , and substituting these leads to

$\dfrac{dy}{dx} = -\dfrac{\left(1 + \frac13 + \frac1{\sqrt3} + \frac1{\sqrt3}\right) \left(1 + \frac13\right)}{\left(1 + \frac13 + 1 + \frac13\right) \left(1 + 1\right)}$

$\dfrac{dy}{dx} = -\dfrac{\left(\frac43 + \frac2{\sqrt3}\right) \times \frac43}{\frac83 \times 2}$

$\dfrac{dy}{dx} = -\dfrac13 - \dfrac1{2\sqrt3}$

as required.

3 0

2 years ago

G(x)=√8x<br> What is the domain of g?

lord [1]

Hello,

Answer B

see my comment on the other question.

7 0

3 years ago

(28÷4)+3+6x5<br><br><br> tell accordingly the correct answer will be marked as brainliest answer

Anvisha [2.4K]

The answer to this expression is 40. Why? Well, we can use PEMDAS in this expression.

P: Parenthesis

So this is our first step:

28 / 4 = 7

Next step: Simplify.

7 + 3 + 6 x 5

Then: E stands for Exponents but we have none so we can move on.

M stands for Multiply so we have our next step:

6 x 5 = 30

Now: Simplify.

7 + 3 + 30

Now that we have a simple equation, we can add the values to get our answer.

7 + 3 = 10
10 + 30 = 40

Therefore, your answer is 40. Whenever you see problems like this, be sure to use PEMDAS for a faster and more accurate evaluation.

Your final answer: 40.

3 0

2 years ago

What is the measure of ZBAC?

IceJOKER [234]

Answer:

80 degrees

Step-by-step explanation:

Sum of the interior angles of a triangle = 180

a + 50 + 50 = 180

a = 80

6 0

2 years ago

Angela asked each member of her class if they ever been to six flags over Georgia the class consists of 10 males and 14 females.

Feliz [49]

Answer:

2 male students didn't visit six falgs.

Step-by-step explanation:

Hello!

You have the following information:

The class has 10 male students and 14 female students.

From the females, 8 visited six flags over Georgia.

And from the total of students of class 16 visited the six flags over Georgia.

Using this information you have to calculate the number of male students that did not visit six flags.

First step: Calculate the number of male students that visited six flags.

The total of students that visited is 16 from those 8 are female then 16 - 8 = 8 male students visited six flags.

Second step: Calculate the number of students that didn't visit it.

From the total of male students in the class, 8 visited six flags so 10 - 8 = 2 male students didn't visit six flags over GA.

I hope this helps!

7 0

3 years ago