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3 years ago

Find all derivatives of y^n of the function y=√x+5

Mathematics

1 answer:

quester [9]3 years ago

3 0

Hello,

As somebody has distroyed my question, (may be he have not understood ?)

i will reply to y=(√x)+5

$\displaystyle \boxed{\dfrac{d^n y}{dx^n} =(-1)^n*n!! *\dfrac{1}{2^n} *x^{-\frac{2n+1}{2} }\\}\\y'=\dfrac{1}{2} *x^{-\frac{1}{2}} \\\\y''=-\dfrac{1}{4} *x^{-\frac{3}{2}} \\...\\$

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Find the product of 3x^2+x-1 and 4x+5

Mkey [24]

Answer:

12x^3 + 19x^2 +x - 5

Step-by-step explanation:

(3x^2 + x - 1 ) (4x + 5)

12x^3 + 15x^2 + 4x^2 + 5x - 4x - 5 use the Distributive

Property* to multiply

each term by each other

term.

12x^3 + 19x^2 +x - 5 simply

*Distribute the first number to 4x, and then by 5. Then distribute x to 4x and 5, and distribute -1 to 4x and 5. By distribute I mean multiply.

8 0

4 years ago

Solve: y= -5 x= y + 3 what is the pair (_,_)

olga nikolaevna [1]

We are given $y=-5$ . Substituting, $x=y+3=-5+3=-2$ .

Thus, our ordered pair $(x, y)$ is $(-2, -5)$ .

8 0

3 years ago

Read 2 more answers

A triangle with vertices at A(20, –30), B(10, –15), and C(5, –20) has been dilated with a center of dilation at the origin. The

Kobotan [32]

Answer:

One-fifth

Step-by-step explanation:

step 1

Find the distance between the origin and the point B

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

O (0,0) and B(10, –15)

substitute

$d=\sqrt{(-15-0)^{2}+(10-0)^{2}}$

$d=\sqrt{325}\ units$

step 2

Find the distance between the origin and the point B'

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

O (0,0) and B'(2,-3)

substitute

$d=\sqrt{(-3-0)^{2}+(2-0)^{2}}$

$d=\sqrt{13}\ units$

step 3

Find the scale factor of the dilation

The scale factor is equal to divide the length of segment OB' by the length of segment OB

$\frac{\sqrt{13}}{\sqrt{325}}=\frac{1}{5}$

One-fifth

4 0

3 years ago

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37th term; a1 = 2.3; d = -2.3

Sindrei [870]

Answer:

37th term of given arithmetic sequence $a_1$ = 2.3; d = -2.3 is -80.5.

Solution:

Given that

Need to determine 37th term, when $a_1$ = 2.3, d = -2.3

Means first term of arithmetic sequence = $a_1$ = 2.3 and common difference d = -2.3

Formula for nth term of arithmetic sequence is

$\mathrm{a}_{\mathrm{n}}=\mathrm{a}_{1}+(\mathrm{n}-1) \mathrm{d}$ --- equation 1

$\text { In our case } a_{1}=2.3, d=-2.3$

We need to determine 37th term so n = 37.

On substituting given values in equation (1) we get

$\mathrm{a}_{37}=\mathrm{a}_{1}+(37-1) \mathrm{d}$

$\begin{array}{l}{\Rightarrow a_{37}=2.3+(37-1)(-2.3)} \\\\ {\Rightarrow a_{37}=2.3(1-36)=2.3 \times 35=-80.5}\end{array}$

Hence 37th term of given arithmetic sequence is -80.5

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3 years ago

Two parallel lines are crossed by a traversal. What is the value of y?

deff fn [24]

Answer:

y = 50 is answers and it is alternate angle

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3 years ago

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