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rodikova [14]
2 years ago
15

Evaluate the indefinite integral.

Mathematics
1 answer:
eduard2 years ago
6 0

Answer:

I believe its C , i took this class

Step-by-step explanation:

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Which graph represents a bike traveling at a constant rate of
vladimir1956 [14]

Answer:

correct ans is option/graph Dbecoz 36/3 = 12

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If the points (0, 0), (-1, 1), and (-2, 2) lie on the graph of function h, then which of the following rules could represent the
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Twice the difference of x and 5 is -33
Elden [556K]
2*(x-5) = -33, so x-5 = -16.5, so x = -11.5

This is assuming that "the difference between a and b" is a-b, which seems to be the accepted interpretation.
3 0
2 years ago
A country's population in 1994 was 182 million. In 2002 it was 186 million. Estimate the population in 2004 using the exponentia
iogann1982 [59]
\bf =ae^{kt}\qquad 
\begin{cases}
1994\impliedby \textit{year 0, starting point}\\
t=0\qquad P=182
\end{cases}\implies 182=ae^{k0}
\\\\\\
182=a\cdot e^0\implies 182=a\cdot 1\implies 182=a
\\\\\\
thus\qquad P=182e^{kt}\\\\
-------------------------------\\\\

\bf P=182e^{kt}\qquad 
\begin{cases}
2002\impliedby \textit{8 years later}\\
t=8\qquad P=186
\end{cases}\implies 186=182e^{k8}
\\\\\\
\cfrac{186}{182}=e^{8k}\implies ln\left( \frac{93}{91} \right)=ln(e^{8k})\implies ln\left( \frac{93}{91} \right)=8k
\\\\\\
\cfrac{ln\left( \frac{93}{91} \right)}{8}=k\implies 0.0027\approx k\implies \boxed{P=182e^{0.0027t}}

what's the population in 2004?  well,  from 1994 to 2004 is 10 years later, so t = 10

plug that in, to get P for 2004
3 0
3 years ago
10) Which two ratios form a proportion? A) 1 : 2 and 4 : 2 B) 1 : 2 and 6 : 3 C) 2 : 1 and 2 : 4 D) 2 : 1 and 6 : 3
Likurg_2 [28]

Answer:

2/1and6/3 because if you do cross multilication they both equal 6

Step-by-step explanation:

8 0
3 years ago
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