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Westkost [7]
3 years ago
15

The partial factorization of x2 – 3x – 10 is modeled with algebra tiles.

Mathematics
2 answers:
lesya692 [45]3 years ago
7 0

Answer:

b

Step-by-step explanation:

got it right

salantis [7]3 years ago
6 0

Answer:

2 positive unit tiles

Step-by-step explanation:

on Edgenuity 2020

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Using slope formula find the slope of the line through the points 0,0 and 3,12 use the pencil and paper
sertanlavr [38]

Answer:

wouldn't it be 3,12.....................

7 0
2 years ago
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Solve for the indicated variable. Include all of your work in your answer. Submit your solution. P = 3r + 2s; for s.
madam [21]
<h3>Given</h3>

P = 3r + 2s

<h3>Find</h3>

the corresponding equation for s

<h3>Solution</h3>

First of all, look at how this is evaluated in terms of what happens to a value for s.

  1. s is multiplied by 2
  2. 3r is added to that product

To solve for s, you undo these operations in reverse order. The "undo" for addition is adding the opposite. The "undo" for multiplication is division (or multiplication by the reciprocal).

... P = 3r + 2s . . . . . . starting equation

... P - 3r = 2s . . . . . . -3r is added to both sides to undo addition of 3r

... (P -3r)/2 = s . . . . . both sides are divided by 2 to undo the multiplication

Note that the division is of everything on both sides of the equation. That is why we need to add parentheses around the expression that was on the left—so the whole thing gets divided by 2.

Your solution is ...

... s = (P - 3r)/2

3 0
3 years ago
On a blueprint, the bedroom wall is 6 in long. the scale factor is 1 to 24. what is the length of the actual wall?
andrezito [222]

Answer:

A

Hope This Helps! :)

6 0
2 years ago
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Which expression is equivalent to square root 55x^7y6/11x^11y^8
Novay_Z [31]

Answer:

\large\boxed{\sqrt{\dfrac{55x^7y^6}{11x^{11}y^8}}=\dfrac{\sqrt5}{x^2y}}

Step-by-step explanation:

\sqrt{\dfrac{55x^7y^6}{11x^{11}y^8}}=\sqrt{\dfrac{55}{11}\cdot\dfrac{x^7}{x^{11}}\cdot\dfrac{y^6}{y^8}}\qquad\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\=\sqrt{5x^{7-11}y^{6-8}}=\sqrt{5x^{-4}y^{-2}}\qquad\text{use}\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\=\sqrt5\cdot\sqrt{x^{-4}}\cdot\sqrt{y^{-2}}=\sqrt5\cdot\sqrt{x^{(-2)(2)}}\cdot\sqrt{y^{(-1)(2)}}\qquad\text{use}\ (a^n)^m=a^{nm}\\\\=\sqrt5\cdot\sqrt{(x^{-2})^2}\cdot\sqrt{(y^{-1})^2}\qquad\text{use}\ \sqrt{a^2}=a

=\sqrt5\cdot x^{-2}\cdot y^{-1}\qquad\text{use}\ a^{-n}=\dfrac{1}{a^n}\to a^{-1}=\dfrac{1}{a}\\\\=\sqrt5\cdot\dfrac{1}{x^2}\cdot\dfrac{1}{y}=\dfrac{\sqrt5}{x^2y}

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3 years ago
Can someone help me in this question please !
prohojiy [21]
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