Given:
let h be the high quality bean
let c be the cheaper bean
h + c = 160
6h + 3.25c = 160*4.97
6h + 3.25c = 795.20
h = 160 - c
6(160 - c) + 3.25c = 795.20
960 - 6c + 3.25c = 795.20
-2.75c = 795.20 - 960
-2.75c = -164.80
c = -164.80 / -2.75
c = 59.92 or 60 lbs
h = 160 - c
h = 160 - 60
h = 100 lbs
Sarah should blend 60 lbs of cheap coffee bean and 100 lbs of high quality coffee bean.
Answer:
x^2+8x+<u>1</u><u>6</u><u>=</u><u>(</u><u>x-4</u><u>)</u><u>^</u><u>2</u>
<em><u>EXPLANATION</u></em><em><u>:</u></em>
<u>(</u><u>a</u><u>+</u><u>b</u><u>)</u><u>^</u><u>2</u><u>=</u><u>a2</u><u>+</u><u>2</u><u>.</u><u>a</u><u>.</u><u>b</u><u>+</u><u>b2</u>
<u>we</u><u> </u><u>have</u><u> </u><u>to</u><u> </u><u>break</u><u> </u><u>the</u><u> </u><u>middle</u><u> </u><u>term</u><u> </u><u>i</u><u>n</u><u> </u><u>2</u><u>a</u><u>b</u><u> </u><u>here</u><u> </u><u>a</u><u> </u><u>is</u><u> </u><u>x</u><u> </u><u>then</u><u> </u><u>2</u><u>x</u><u>b</u><u>=</u><u>8</u><u>x</u><u>,</u><u> </u><u>=</u><u>></u><u> </u><u>b</u><u>=</u><u>4</u><u>,</u><u> </u><u>but</u><u> </u><u>value</u><u> </u><u>of</u><u> </u><u>a</u><u> </u><u>and</u><u> </u><u>b</u><u> </u><u>to</u><u> </u><u>get</u><u> </u><u>the</u><u> </u><u>req</u><u>uired</u><u> </u><u>equation</u><u>!</u>
I think D but don’t take my word for it
<h2>
Hello!</h2>
The answer is:

<h2>
Why?</h2>
To solve the problem we need to add/subtract like terms. We need to remember that like terms are the terms that share the same variable and the same exponent.
For example, we have:

We have that we were able to add just the terms that were sharing the same variable and exponenr (x for this case).
So, we are given the expression:

Hence, the answer is:

Have a nice day!
Answer:
112
Step-by-step explanation:
correct me if im wrong.
I got this from doing 30 percent out of 160
160×0.30
160-48=112