Ask question

Ask question

All categories

3 years ago

8

If a driver who is under the age of 21 is stopped by a law enforcement officer and has a blood alcohol level of 0.02 or greater

driving privilege for the driver will be suspended for?

Computers and Technology

1 answer:

lions [1.4K]3 years ago

5 0

having their driving privilege suspended for six months.

You might be interested in

Write a Scheme function called "sum" which takes an input function func and a nonnegative number n and outputs the value

solong [7]

Answer:

function sum(number) {

if (number == 1) {

return 1;

}

return number + sum(number -1);

}

Explanation:

This is a recursive function, it means that is a function that calls itself for example: if you call the function with sum(5) the process is :

sum(5)

|______ 5 + sum(4)

|_______ 4 + sum(3)

|______ 3 + sum(2)

|_____2 + sum(1)

|_____ 1

the result is 1+2+3+4+5 = 15

7 0

3 years ago

____ are commonly used for communication between OS components, for queuing requests to an OS service, and for exchanging messag

vekshin1

Answer:

C. Pipes

Explanation:

Pipes are medium of communication between two or more interrelated processes. It is used for communication between operating system components. It is also used in exchanging messages between components of large programs. It implements interprocess communications through an interface. It passes information from one program process to another.

3 0

3 years ago

Read 2 more answers

Help me guys pleassssssssse

Readme [11.4K]

Answer:

is there a word bank??

Explanation:

8 0

2 years ago

A computer retail store has 15 personal computers in stock. A buyer wants to purchase 3 of them. Unknown to either the retail st

Dima020 [189]

Answer:

a. 1365 ways

b. Probability = 0.4096

c. Probability = 0.5904

Explanation:

Given

PCs = 15

Purchase = 3

Solving (a): Ways to select 4 computers out of 15, we make use of Combination formula as follows;

$^nC_r = \frac{n!}{(n-r)!r!}$

Where $n = 15\ and\ r = 4$

$^{15}C_4 = \frac{15!}{(15-4)!4!}$

$^{15}C_4 = \frac{15!}{11!4!}$

$^{15}C_4 = \frac{15 * 14 * 13 * 12 * 11!}{11! * 4 * 3 * 2 * 1}$

$^{15}C_4 = \frac{15 * 14 * 13 * 12}{4 * 3 * 2 * 1}$

$^{15}C_4 = \frac{32760}{24}$

$^{15}C_4 = 1365$

<em>Hence, there are 1365 ways </em>

Solving (b): The probability that exactly 1 will be defective (from the selected 4)

First, we calculate the probability of a PC being defective (p) and probability of a PC not being defective (q)

<em>From the given parameters; 3 out of 15 is detective;</em>

So;

$p = 3/15$

$p = 0.2$

$q = 1 - p$

$q = 1 - 0.2$

$q = 0.8$

Solving further using binomial;

$(p + q)^n = p^n + ^nC_1p^{n-1}q + ^nC_2p^{n-2}q^2 + .....+q^n$

Where n = 4

For the probability that exactly 1 out of 4 will be defective, we make use of

$Probability = ^nC_3pq^3$

Substitute 4 for n, 0.2 for p and 0.8 for q

$Probability = ^4C_3 * 0.2 * 0.8^3$

$Probability = \frac{4!}{3!1!} * 0.2 * 0.8^3$

$Probability = 4 * 0.2 * 0.8^3$

$Probability = 0.4096$

Solving (c): Probability that at least one is defective;

In probability, opposite probability sums to 1;

Hence;

<em>Probability that at least one is defective + Probability that at none is defective = 1</em>

Probability that none is defective is calculated as thus;

$Probability = q^n$

Substitute 4 for n and 0.8 for q

$Probability = 0.8^4$

$Probability = 0.4096$

Substitute 0.4096 for Probability that at none is defective

Probability that at least one is defective + 0.4096= 1

Collect Like Terms

Probability = 1 - 0.4096

Probability = 0.5904

8 0

2 years ago

Select the correct answer from each drop-down menu. Kristian is a cybersecurity professional. She is writing a book called The D

Papessa [141]

Data sharing, maintaining security

<u>Explanation:</u>

Kristian is a cybersecurity professional. She is writing a book called The Door Toward Cybersecurity. Organizations should avoid any data <u>sharing or exchange</u> while servers are transmitting information. This will help organizations keep the information intact and maintain <u>security.</u> If any info or data shared when the servers are transmitting the info, then it may lead to the loss of security, and the information gets leaked. So it must be avoided to share while transmission of info using the servers.

3 0

2 years ago

Read 2 more answers