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lions [1.4K]
3 years ago
7

the circleville pumpkin show in circleville, ohio boasts the world's largest pumpkin pie. The pie weighs 250 pounds an 5 feet in

diameter. Find the diameter of the pie in centimeters in 3 ft = 91.44 cm. Write and use an algebraic proportion to solve
Mathematics
1 answer:
adell [148]3 years ago
6 0

Answer:

br

Step-by-step explanation:

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Which of the following data sets is bimodal?
Ivahew [28]
The mode indicates the highest frequency of a st of value (the most repeated data point).

In {23, 43, 43, 46, 43, 28, 12, 28, 28} we notice that 2 values are being repeated with the same frequency , that is 43 (3 times) & 28 (3 times).
This set is then bimodal
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Plot the line for the equation on graph. y−5=3/2(x−2)
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The answer in mx+b=y form is y=3/2x+3.

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Without solving what can you tell about the solution
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Answer:

n has to be negative

8 0
3 years ago
What is the slope of,<br> (-2,1) and (5,4)?
Neporo4naja [7]

Answer:

\frac{3}{7}

Step-by-step explanation:

\frac{4-1}{5--2} =

\frac{4-1}{5+2} =

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5 0
3 years ago
Air pressure may be represented as a function of height (in meters) above the
denis-greek [22]

Answer: OPTION C.

Step-by-step explanation:

<h3> The complete exercise is: "Air pressure may be represented as a function of height (in meters) above the surface of the Earth, as shown below:</h3><h3>  P(h) =P_0e^{-0.00012h} </h3><h3> In this function P_o   is the air pressure at the surface of the earth, and h is the height above the surface of the Earth, measured in meters. At what height will the air pressure equal 50% of the air pressure at the surface of the Earth"</h3><h3></h3>

Given the following function:

P(h) =P_0e^{-0.00012h}

In order to calculate at what  height the air pressure will be equal 50% of the air pressure at the surface of the Earth, you can follow these steps:

1. You need to substitute P(h)=0.5P_o into the function:

0.5P_o=P_0e^{-0.00012h}

2. Finally, you must solve for h.

Remember the following property of logarithms:

ln(b)^a=a*ln(b)\\\\ln(e)=1

Then, you get this result:

0.5P_o=\frac{P_o}{e^{0.00012h}}\\\\(0.5P_o)(e^{0.00012h})=P_o\\\\e^{0.00012h}=\frac{P_o}{0.5P_o}\\\\ln(e)^{0.00012h}=ln(2)\\\\0.00012h*1=ln(2)\\\\h=\frac{ln(2)}{0.00012}\\\\h=5576.2

7 0
4 years ago
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