The length of pencil A is 5 cm
<em><u>Solution:</u></em>
Let the length of pencil A be "x"
Let the length of pencil B be "y"
Let the length of pencil C be "z"
<em><u>The total length of pencils A, B and C is 29 cm</u></em>
Therefore,
length of pencil A + length of pencil B + length of pencil C = 29
x + y + z = 29 ------------ eqn 1
<em><u>Pencil A is 11 cm shorter then pencil B</u></em>
x = y - 11 ------- eqn 2
<em><u>Pencil B is twice as long a pencil C</u></em>
y = 2z
------ eqn 3
<em><u>Substitute eqn 2 and eqn 3 in eqn 1</u></em>
<em><u>Substitute y = 16 in eqn 2</u></em>
x = 16 - 11
x = 5
Thus length of pencil A is 5 cm
Answer: X=2
Step-by-step explanation:
Assuming the function is
All logarithmic functions, despite their base, has a vertical asymptote at argument = 0.
That is not changed by the vertical stretching made by the 4 which multiplies the logarithm nor the vertical shift made by the +5.
In this case the argument is x - 2, then the vertical asymptote is:
x - 2 = 0
Answer:
12,664
Step-by-step explanation:
Answer:
a. 28˚
b. 76˚
c. 104˚
d. 56˚
Step-by-step explanation
a. because angle between tangent and chord is equal to the angle(s) in alternate segment.
b. because angles in triangles add up to 180˚, 180-28=152 and because isosceles triangle, 152/2=76˚
c. because angles in triangles add up to 180˚ and opposite angles in a cyclic quadrilateral add up to 180˚, 31+76=107, 180-107=73, 73-28=45, angles in triangle so 180-(31+45)=104˚
d. 28*2=56˚ because angles at circumference are half angles at centre
