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3 years ago

Please help, I need this work done.

Mathematics

1 answer:

tekilochka [14]3 years ago

5 0

Slope = (8 - 0)/(0 - 4) = -2
y intercept b = 8

y = mx + b where m = - 2 and b = 8
So equation y = -2x + 8

Answer
D. last one
y = -2x + 8

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What property is demonstrated by 7+h=h+7

julia-pushkina [17]

Answer:

commutative property

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2 years ago

Read 2 more answers

Y = 7/2x + 10 y = -7/2x - 1/10 these lines have perpendicular slopes. True or false?

forsale [732]

Answer: This is False because they don't go together and it doesn't make sense.

Step-by-step explanation:

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3 years ago

Read 2 more answers

Verify the identity cos quantity x plus pi divided by two = -sin x

In-s [12.5K]

Answer:

Identity is verified.

Step-by-step explanation:

We have to verify the identity $cos(x+\frac{\pi }{2}) = (- sinx)$

To prove any identity we always prove one side(either left hand side or right hand side) of the equation equal to the other side.

In this identity we take the left hand side first

$cos(x+\frac{\pi}{2})$

$=cosx\times cos(\pi/2)-sinx\times sin(\pi/2))$ (as we know cos(a+b) = cosa×cosb-sina×sinb)

$= cosx\times0-sinx\times1$

$= 0-sinx$

= - sinx ( Right hand side)

Hence identity is proved.

6 0

4 years ago

Write in simplest form: <img src="https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B24a%5E%7B10%7Db%5E%7B6%7D%7D" id="TexFormula1" ti

Charra [1.4K]

Answer:

$2a^3b^2\sqrt[3]{3a}$

Step-by-step explanation:

Use the following rules for exponents:

$a^m*a^n=a^{m+n}\\\\\sqrt[3]{x^3}=x$

Simplify 24. Find two factors of 24, one of which should be a perfect cube:

$8*3=24\\\\2^3=8$

Insert:

$\sqrt[3]{2^3*3a^{10}b^6}$

Now split the exponents. Split 10 into as many 3's as possible:

$10=3+3+3+1$

Insert as exponents:

$\sqrt[3]{2^3*3*a^3*a^3*a^3*a^1*b^6}$

Split 6 into as many 3's as possible:

$6=3+3$

Insert as exponents:

$\sqrt[3]{2^3*3*a^3*a^3*a^3*a^1*b^3*b^3}$

Now simplify. Any terms with an exponent of 3 will be moved out of the radical (rule #2):

$2\sqrt[3]{3*a^3*a^3*a^3*a^1*b^3*b^3}\\\\\\2*a*a*a\sqrt[3]{3*a^1*b^3*b^3}\\\\\\2*a*a*a*b*b\sqrt[3]{3*a^1}$

Simplify:

$2a^3b^2\sqrt[3]{3a}$

:Done

6 0

3 years ago

Which of the following is the product of the rational expression shown below

wolverine [178]

Option C: $\frac{x^{2}-9}{x^{2}-4}$ is the product of the rational expression.

Explanation:

The given rational expression is $\frac{x+3}{x+2} \cdot \frac{x-3}{x-2}$

We need to determine the product of the rational expression.

Product of the rational expression:

Let us multiply the rational expression to determine the product of the rational expression.

Thus, we have;

$\frac{(x+3)(x-3)}{(x+2)(x-2)}$

Let us use the identity $(a+b)(a-b)=a^2-b^2$ in the above expression.

Thus, we get;

$\frac{x^{2} -3^2}{x^{2} -2^2}$

Simplifying the terms, we get;

$\frac{x^{2}-9}{x^{2}-4}$

Thus, the product of the rational expression is $\frac{x^{2}-9}{x^{2}-4}$

Hence, Option C is the correct answer.

6 0

3 years ago