3 years ago

What is 4.62 expressed as an improper fraction in simplest form?

Mathematics

2 answers:

sp2606 [1]3 years ago

6 0

4 62/100= 4 31/50= 231/50

Sladkaya [172]3 years ago

5 0

4 31/50 as a mixed number
231/50 as an improper fraction

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Could someone pls help me out? Thank u so much

vesna_86 [32]

Answer:

$25

Step-by-step explanation:

c=30−(0.25)(20)

c=30+(−5)

c=(30+(−5)

30-5

Combine Like Terms

c=25

8 0

3 years ago

(−7.9 + (−3.4)) + (8.2 + 2.1)

Natasha_Volkova [10]

The answer is -1, when adding both sides.

8 0

3 years ago

Solve for x. −1.5x = −2.55 A) −1.5 B) 1.5 C) 1.7 D) 1.9

Liono4ka [1.6K]

Answer:

Step-by-step explanation:

-1.5x=-2.55

1.5x=2.55

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8 0

3 years ago

Evaluate the following integral in cylindrical coordinates triple integral 1/(1+x^2+y^2) dzdxdy z=0..2 y=0..square root(1-x^2) x

sertanlavr [38]

In cylindrical coordinates, we take

$x=r\cos\theta$

$y=r\sin\theta$

$z=z$

so that $\mathrm dx\,\mathrm dy\,\mathrm dz=r\,\mathrm dr\,\mathrm d\theta\,\mathrm dz$ .

We have

$1+x^2+y^2=1+r^2$

and the integral is

$\displaystyle\int_0^2\int_0^\pi\int_0^1\frac r{1+r^2}\,\mathrm dr\,\mathrm d\theta\,\mathrm dz=\frac{\ln2}2\int_0^2\int_0^\pi\mathrm d\theta\,\mathrm dz=\boxed{\pi\ln2}$

8 0

3 years ago

Rebecca went swimming yesterday. After a while she had covered one fifth of her intended distance. After swimming six more lengt

alukav5142 [94]

Answer:

Option E.

Step-by-step explanation:

Let the intended length of Rebecca's swimming is = x units

and we assume the length of the pool = l units

Now it is given in the question that " She covers one fifth of her intended distance "

That means distance covered = $\frac{x}{5}$

" After swimming six more lengths of the pool she had covered one quarter of her intended distance"

So $\frac{x}{5}+6(l)=\frac{x}{4}$

$6l=\frac{x}{4}-\frac{x}{5}$

$6l=\frac{x}{20}$

x = 20×(6l)

x = 120l

Therefore, Rebecca has to complete 120 lengths of the pool.

Option E is the answer.

4 0

3 years ago