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Irina18 [472]
3 years ago
8

Prove that Zn Zn is notisomorphic to any subgroup of Zm for any m.

Mathematics
1 answer:
WINSTONCH [101]3 years ago
5 0

Answer and Step-by-step explanation:

Every group homomorphism ϕ:Zn→Zm extends in a unique way to a linear transformation T:Qn→Qm of vector spaces over Q.

Moreover, ϕ is injective iff T is injective. But T being injective implies n≤m.

Applying this to both ϕ and ϕ−1, we conclude that n≤m≤n.

NOTE:

The proof and step-by-step explanation is in the attachment below

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Y=.5x+4 <br> Y= -.25x^2+5 <br> Using the quadratic formula, what are the solutions?
Aleksandr-060686 [28]

Hi there!

\large\boxed{x = -1 \pm \sqrt{5}}

We can solve by setting both equations equal to each other:

.5x + 4 = -.25x² + 5

Move everything to one side:

0 = -.25x² - .5x + 1

Multiply both sides by 4 to cancel out the decimals:

0 = -x² - 2x + 4

Factor out negative from both sides:

0 = x² + 2x - 4

Use the quadratic formula:

\frac{-b \pm \sqrt{b^2-4ac}}{2a}

Plug in the corresponding terms:

x = \frac{-2 \pm \sqrt{4-4(-4)(1)}}{2}

Simplify:

x = \frac{-2 \pm \sqrt{4 + 16}}{2}\\\\x = \frac{-2 \pm \sqrt{20}}{2}

Simplify the radical to reduce:

x = \frac{-2 \pm 2\sqrt{5}}{2}

Divide all terms by 2:

x = -1 \pm \sqrt{5}

4 0
2 years ago
Write the ratio 3/7 to 9 as a fraction in simplest form
qaws [65]

Answer:

Step-by-step explanation:

Write the ratio of 3/7 to 9 as a fraction in simplest form

-----

(3/7):9

 

Multiply by 7

= 3:63

= 1:21

P.S ... I found this on the internet

4 0
3 years ago
Georgia. 0.029 can be written as 29 / 100 is he correct
bija089 [108]
Yes because if you write it it's twenty nine out of one hundred
7 0
3 years ago
Read 2 more answers
Ray's pizza serves small and LG pizza. a small pizza has a diameter of 10inches and is sliced into 6 equal slices.a large pizza
Andrew [12]
  Amount of pizza eaten by Charlie.
 
7/6× 22/7 × (101/2)² =9350.91667

  Amount of pizza eaten by Julie

5/12 × 22/7 × 90.5² = 10725.3273

   Answer = Julie
3 0
2 years ago
Find the sum of all numbers from 150 to 200 which are divisible by7​
podryga [215]

Step-by-step explanation:

The sum is 1225

Solution : 

The numbers from 150 to 200 divisible by 7 are 154,161 ,168,…., 196

Here, a=154,d=7a=154,d=7 and tn=196tn=196

tn=a+(n−1)dtn=a+(n-1)d …(Formula )

∴196=154+(n−1)×7∴196=154+(n-1)×7 …(Substituting the values )

∴196−154=(n−1)×7∴196-154=(n-1)×7

∴427=n−1∴427=n-1 ∴n−1=6∴n-1=6 ∴n=7∴n=7

Now, we find the sum of 7 numbers.

Sn=n2[t1+tn]Sn=n2[t1+tn] ...(Formula )

=72[154+196)=72[154+196)

=72×350=72×350

=7×175=7×175

=1225

8 0
3 years ago
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